A right pyramid stands on a base 16 cm square and its height

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A right pyramid stands on a base 16 cm square and its height is 15 cm. The area (in cm2) of its slant surface is

Lateral surface area =	1	× perimeter of base × slant height
	2

[∵ Slant height = √8² + 15² = √64 + 25 = √289 = 17 cm]

∴ Required area =	1	× 64 × 17 = 544 sq.cm.
	2