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The base of a right pyramid is a square of side 10 cm. If the height of the pyramid is 12 cm, then its total surface area is
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- 400 cm²
- 460 cm²
- 260 cm²
- 360 cm²
- 400 cm²
Correct Option: D
Slant height = BE = √12 + 5 = √144 + 25
= √169 = 13 cm.
| ∴ Lateral surface of pyramid = | × perimeter of base × slant height | |
| 2 |
| = | × 40 × 13 = 260 sq. cm. | |
| 2 |
Area of base = 10 × 10 = 100 sq. cm.
∴ Total surface area = (260 + 100) sq. cm. = 360 sq. cm.
