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The lateral surface area of frustum of a right circular cone, if the area of its base is 16π cm² and the diameter of circular upper surface is 4 cm and slant height is 6 cm, will be
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- 30π cm²
- 48π cm²
- 36π cm²
- 60π cm²
- 30π cm²
Correct Option: C
According to the question,
πR² = 16π
⇒ R² = 16
⇒ R = 16 = 4 cm.
∴ Required area = π(R + r)l
= π(4 + 2) × 6 = 36π sq. cm.
