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  1. The perimeter of a triangle is 40cm and its area is 60 cm². If the largest side measures 17cm, then the length (in cm) of the smallest side of the triangle is
    1. 4
    2. 6
    3. 8
    4. 15
Correct Option: C

Smallest side of the triangle = x cm (let)
∴ Second side of triangle = 40 – 17 – x = 23 – x

Semi-perimeter = s =
40
= 20
2

∴ √s (s - a)(s - b)(s - c)
⇒ √20(20 - 17)(20 - x)(20 - 23 - x) = 60
⇒ (20 - x)(x - 3) = 60
⇒ (20 – x) (x – 3) = 60
⇒ 20x – 60 –x² + 3x = 60
⇒ x² – 23x + 120 = 0
⇒ x² – 15x – 8x + 120 = 0
⇒ x (x – 15) – 8 (x – 15) = 0
⇒ (x – 8) (x – 15) = 0
⇒ x = 8 or 15
⇒ Smallest side = 8 cm



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