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  1. Two circles with centres A and B and radius 2 units touch each other externally at ‘C’. A third circle with centre ‘C’ and radius ‘2’ units meets other two at D and E. Then the area of the quadrilateral ABDE is
    1. 2√2 sq. units
    2. 3√3 sq. units
    3. 3√2 sq. units
    4. 2√3 sq. units
Correct Option: B


ABDE will be a trapezium
AB = 4 units

DE =
1
AB = 2 units
2

FB = 1 unit, BD = 2 units.
⇒ DF = √2² - 1² = √3units
∴ Area of ABDE =
1
(AB + DE) × DF
2

=
1
(4 + 2) × √3
2

= 3√3 sq. units



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