A right pyramid stands on a square base of diagonal 10√2

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A right pyramid stands on a square base of diagonal 10√2 cm. If the height of the pyramid is 12 cm, the area (in cm²) of its slant surface is

Side of square base =	1	× 10√2 = 10 cm.
	√2

Slant height = √5² + 12² = 13 cm

∴ Area of the lateral surface =	1	× perimeter of base × slant height
	2

=	1	× 40 × 13 = 260 sq.cm.
	2