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The radius of each circle is ‘a’. Then the area of the shaded portion is :
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a² 
√3 - π 
sq. units 2 - a(πa² - √3) sq. units
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a² - π √3 sq. units 2
- None of these
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Correct Option: A
AB = BC = CA = 2a
| Area of ∆ABC = | × (2a)² | |
| 4 |
= √3a²
| Area of three sectors = 3 × | × πa² = | ||
| 360 | 2 |
| ∴ Area of shaded region = √3a² - | ||
| 2 |
| = a² | | √3 - | | sq.units | |
| 2 |
