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If average of 20 observations x1, x2, ....., x20 is y, then the average of x1 – 101, x2 – 101, x3 – 101, ....., x20 –101 is
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- y – 20
- y – 101
- 20y
- 101y
- y – 20
Correct Option: B
Given Here , average of 20 observations x1, x2, ....., x20 = y
Now , we have
Required average = | |
20 |
Required average = | |
20 |
Required average = | - | ||
20 | 20 |
Hence , Required average = y - 101