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The average of 6 consecutive natural numbers is K. If the next two natural numbers are also included, how much more than K will the average of these 8 numbers be?
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- 1.3
- 1
- 2
- 1.8
- 1.3
Correct Option: B
Let 6 consecutive natural numbers are y , y + 1 , y + 2 , y + 3 , y + 4 , y + 5
The average of 6 consecutive natural numbers = K
Sum of 6 consecutive natural numbers = y + ( y + 1 ) + ( y + 2 ) + ( y + 3 ) + ( y + 4 ) + ( y + 5 )
y + y + 1 + y + 2 + y + 3 + y + 4 + y + 5 = 6K
⇒ 6y + 15 = 6K
⇒ y + | = K | |
6 |
⇒ y + | = K..........(1) | |
2 |
Again,
8 |
= | + | = y + | ..........(ii) | |||
8 | 8 | 2 |
Now, y + | - y - | = 1 | ||
2 | 2 |