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The average weight of three men A, B and C is 84 kg. D joins them and the average weight of the four becomes 80 kg. If E whose weight is 3 kg more than that of D, replaces A, the average weight of B, C, D and E becomes 79 kg. The weight of A is
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- 65 kg.
- 70 kg.
- 75 kg.
- 80 kg.
- 65 kg.
Correct Option: C
The average weight of three men A, B and C = 84 kg
⇒ Total weight of A, B and C = 84 × 3 = 252 kg.
Again, the average weight of the four men = 80 kg
⇒ A + B + C + D = 80 × 4 = 320 kg.
∴ D = ( A + B + C + D ) - ( A + B + C ) = (320 – 252) kg. = 68 kg.
E = 68 + 3 = 71 kg.
B + C + D + E = 79 × 4 = 316 kg.
Now, (A + B + C + D) – (B + C + D +E) = (320 – 316) kg.
∴ A – E = 4 kg.
⇒ A = 4 + E = 4 + 71 = 75 kg