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The average run of a player is 32 out of 10 innings. How many runs must he make in the next innings so as to increase his average by 6 ?
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- 38
- 40
- 6
- 98
- 38
Correct Option: D
Let runs scored in the next innings = n
According to the question,
⇒ 10 × 32 + n = 11 × 38
⇒ 320 + n = 418
⇒ n = 418 – 320 = 98
Second method to solve this question with the help of given formula :
Here, T = 32, N= (10 + 1) = 11, t = 6
Required Runs = T + Nt
Hence , Required Runs = 32 + 11 × 6 = 32 + 66 = 98
