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Seven years ago, the average age of A, B and C was 51 years. If A is 3 years older than B and B is 3 years older than C then the present ages of A, B and C are (in years)
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- 61, 58 and 55
- 54, 51, and 48
- 55, 58, and 61
- 48, 51 and 54
- 61, 58 and 55
Correct Option: A
Given that , Seven years ago, the average age of A, B and C = 51 years.
Sum of the present ages of A, B and C = (51 × 3 + 3 × 7) years
Sum of the present ages of A, B and C = (153 + 21) years = 174 years
According to question ,
Now , A = B + 3 = C + 6
⇒ B = C + 3
∴ A + B + C = 174
⇒ C + 6 + C + 3 + C = 174
⇒ 3C = 174 – 9 = 165
⇒ C = 165 ÷ 3 = 55 years
∴ A = C + 6 = 55 + 6 = 61 years
B = C + 3 = 55 + 3 = 58 years
