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The area of the triangle formed by the lines 5x + 7y = 35, 4x + 3y = 12 and x-axis is
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160 sq.unit 13 -
150 sq.unit 13 -
140 sq.unit 13 - 10 sq.unit
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Correct Option: A
Given that :- 5x + 7y = 35... (i)
4x + 3y = 12... (ii)
By equation (i) × 4 – (ii) × 5
On subtracting (20x + 28y = 140) - (20x + 15y = 60) ⇒ 13y = 80
| ⇒ y = | = Height of triangle | |
| 13 |
Point of intersection on x-axis of equation
5x + 7y = 35
⇒ 5x + 7 × 0 = 35
⇒ 5x = 35 ⇒ x = 7
∴ (7, 0)
Similarly, point of intersection of
4x + 3y = 12 = (3, 0)
∴ Base = 7 – 3 = 4
| ∴ Area = | × 4 × | = | sq.unit | |||
| 2 | 13 | 13 |
