Out of three numbers, the first is twice the second and

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Out of three numbers, the first is twice the second and is half of the third. If the average of three number is 56, the three number in order are ?

Let second number = x
So, first number = 2x and third number= 4x
∴ ( x + 2x + 4x ) / 3 = 56
⇒ 7x = 168
⇒ x = 24
So the numbers are 48,24, 96,