Materials Science and Manufacturing Engineering Miscellaneous


Materials Science and Manufacturing Engineering Miscellaneous

Materials Science and Manufacturing Engineering

  1. A grinding ratio of 200 implies that the









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    Grinding ratio is defined as

    =
    Volume of work material removed (Vm)
    Volume of wheel wear (Vw)

    200 =
    Volume of work material removed (Vm)
    Volume of wheel wear (Vw)

    Grinding wheel wears 0.005 times the volume of material removed.

    Correct Option: B

    Grinding ratio is defined as

    =
    Volume of work material removed (Vm)
    Volume of wheel wear (Vw)

    200 =
    Volume of work material removed (Vm)
    Volume of wheel wear (Vw)

    Grinding wheel wears 0.005 times the volume of material removed.


  1. Using the Taylor's tool life equation with exponent n = 0.5, if the cutting speed is reduced by 50%, the ratio of new tool life to original tool life is









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    V2 =
    V1
    2

    V1T10.5 = V2T20.5
    V1T10.5 =
    V1
    T20.5
    2

    T2
    0.5= 2
    T1

    T2
    = 21/0.5 = 4
    T1

    Correct Option: A

    V2 =
    V1
    2

    V1T10.5 = V2T20.5
    V1T10.5 =
    V1
    T20.5
    2

    T2
    0.5= 2
    T1

    T2
    = 21/0.5 = 4
    T1



  1. During the turning of a 20 mm diameter steel bar at a spindle speed of 400 rpm, a tool life of 20 minute is obtained. When the same bar is turned at 200 rpm, the tool life becomes 60 minute. Assume that Taylor's tool life equation is valid. When the bar is turned at 300 rpm, the tool life (in minute) is approximately ____ .









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    NA

    Correct Option: B

    NA


  1. In an orthogonal machining with a tool of 9° orthogonal rake angle, the uncut chip thickness is 0.2 mm. The chip thickness fluctuates between 0.25 mm and 0.4 mm. The ratio of the maximum shear angle to the minimum shear angle during machining is______.









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    Given α = 9°
    t = 0.2 mm
    t c max = 0.4 mm
    tcmin = 0.25 mm

    or Φmin = 28.18°

    Ratio =
    Φmax
    =
    42.09
    = 1.494
    Φmin28.18

    Correct Option: C

    Given α = 9°
    t = 0.2 mm
    t c max = 0.4 mm
    tcmin = 0.25 mm

    or Φmin = 28.18°

    Ratio =
    Φmax
    =
    42.09
    = 1.494
    Φmin28.18



  1. A block of length 200 mm is machined by a slab milling cutter 34 mm in diameter. The depth of cut and table feed are set at 2 mm and 18 mm/minute, respectively. Considering the approach and the over travel of the cutter to be same, the minimum estimated machining time per pass is minutes.









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    L = 200 + 2x
    x = √172 - 152 = 8
    ∴ L= 216 mm

    Time =
    L
    =
    216
    = 12 min
    fN18

    Correct Option: C


    L = 200 + 2x
    x = √172 - 152 = 8
    ∴ L= 216 mm

    Time =
    L
    =
    216
    = 12 min
    fN18