Materials Science and Manufacturing Engineering Miscellaneous


Materials Science and Manufacturing Engineering Miscellaneous

Materials Science and Manufacturing Engineering

  1. The thickness of a plate is reduced from 30 mm to 10 mm by successive cold rolling passes using identical rolls of diameter 600 mm. Assume that there is no change in width. If the coefficient of friction between the rolls and the workpiece is 0.1, the minimum number of passes required is









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    hi = 30 mm     µ = 0.1 D = 60 mm
    hf = 10 mm     R = 300 mm
    Δh = 20 mm
    Draft of single pass
    (Δh)1 = µ2 = (0.11)2 × 300

    No = passes =
    20
    = 6.67 ≃ 7 passes.
    3

    Correct Option: D

    hi = 30 mm     µ = 0.1 D = 60 mm
    hf = 10 mm     R = 300 mm
    Δh = 20 mm
    Draft of single pass
    (Δh)1 = µ2 = (0.11)2 × 300

    No = passes =
    20
    = 6.67 ≃ 7 passes.
    3


  1. In a rolling process, the roll separating force can be decreased by









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    As roll diameter decreases for the same reduction the contact length decreases. So less force will be required.

    Correct Option: A

    As roll diameter decreases for the same reduction the contact length decreases. So less force will be required.



  1. Anisotropy in rolled components is caused by









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    When a material having different value of property in different Direction, called as anisotropic material

    Correct Option: D

    When a material having different value of property in different Direction, called as anisotropic material


  1. In a rolling process, thickness of a strip is reduced from 4 mm to 3 mm using 300 mm diameter rolls rotating at 100 rpm. The velocity of the strip (in m/sec) at the neutral point is









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    V =
    πDN
    60

    At Neutral Point, Roll velocity and plate velocity are equal.

    Correct Option: A

    V =
    πDN
    60

    At Neutral Point, Roll velocity and plate velocity are equal.



  1. The maximum possible percentage reduction in area per pass during wire drawing of an ideal plastic material without friction is of the order of









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    σd = σ0
    Ai
    Af

    Ai
    = R → Extrusion Ratio
    Af

    If σd = σ0 {Maximum possible Reduction}
    1 = ln
    Ai
    Af

    e =
    Ai
    Af

    % Reduction =
    Ai − Af
    × 100 = 1 −
    1
    × 100
    Aie

    % Reduction = 63%

    Correct Option: C

    σd = σ0
    Ai
    Af

    Ai
    = R → Extrusion Ratio
    Af

    If σd = σ0 {Maximum possible Reduction}
    1 = ln
    Ai
    Af

    e =
    Ai
    Af

    % Reduction =
    Ai − Af
    × 100 = 1 −
    1
    × 100
    Aie

    % Reduction = 63%