Biochemical Miscellaneous


Biochemical Miscellaneous

  1. Choose the correct completion of the following statement. ​​
    A fermenter sterilisation in situ is less efficient than continuous heat sterilisation because ​​









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    It uses longer heating time during which heat is lost.

    Correct Option: B

    It uses longer heating time during which heat is lost.


  1. In secondary metabolism two distinct phases- trophophase and idiophase refer respectively to









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    In secondary metabolism two phases are apparent: trophophase and idiophase. Trophophase is the growth phase of the culture; idiophase is the time when the secondary metabolites are formed. The success of the idio-phase is dependent on the trophophase.

    Correct Option: A

    In secondary metabolism two phases are apparent: trophophase and idiophase. Trophophase is the growth phase of the culture; idiophase is the time when the secondary metabolites are formed. The success of the idio-phase is dependent on the trophophase.



  1. A bacterial culture with an approximate biomass composition of CH1.8O0.5N0.2 is grown aerobically on a defined medium containing glucose as the sole carbon source and ammonia being the nitrogen source. In this fermentation, biomass is formed with a yield coefficient of 0.35 gram dry cell weight per gram of glucose and acetate is produced
    with a yield coefficient of 0.1 gram acetate per gram of glucose. The respiratory coefficient for the above culture will be ​​









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    Yx/s = 0.35 g/g , YP/S = 0.1
    g acetate
    g dry cell
    g glucoseg glucose

    The respiratory coefficient ​​
    Respiratory quotient =
    Moles of CO2 formed
    Moles of CO2 consumed

    =
    5
    = 1.01
    4.95

    C6 H12 O6 + b NH3 + O2 → CH1.8O0.5 N0.2 + eH2O + f CO2 ​​
    C : 6a = 1 + f ​...(1) ​​
    H : 12a + 3b = 1.8 + 2e ​...(2) ​​
    O : 6a + 2d = 0.5 + e +  2F ​...(3)
    b = 0.2 ​​
    N : b = 0.2
    ​​∴ ​​12a​ = 1.2 + 2e ​​​​
    6a ​= 1 + F  ​​
    Let if ​a ​= 1, i.e. F = 5 ​​​​
    e​ = 5.4
    ​​​​d​ = 4.95 ​​​​
    b ​= 0.2
    ​​​​a ​= 1 ​

    Correct Option: B

    Yx/s = 0.35 g/g , YP/S = 0.1
    g acetate
    g dry cell
    g glucoseg glucose

    The respiratory coefficient ​​
    Respiratory quotient =
    Moles of CO2 formed
    Moles of CO2 consumed

    =
    5
    = 1.01
    4.95

    C6 H12 O6 + b NH3 + O2 → CH1.8O0.5 N0.2 + eH2O + f CO2 ​​
    C : 6a = 1 + f ​...(1) ​​
    H : 12a + 3b = 1.8 + 2e ​...(2) ​​
    O : 6a + 2d = 0.5 + e +  2F ​...(3)
    b = 0.2 ​​
    N : b = 0.2
    ​​∴ ​​12a​ = 1.2 + 2e ​​​​
    6a ​= 1 + F  ​​
    Let if ​a ​= 1, i.e. F = 5 ​​​​
    e​ = 5.4
    ​​​​d​ = 4.95 ​​​​
    b ​= 0.2
    ​​​​a ​= 1 ​


  1. A culture of bacteria is infected with bacteriophage at a multiplicity of 0.3. The probability of a single cell infected with 3 phages is ​









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    Probability of bacteria getting infected by a single bacteriophage= 0.3 i.e. P(A)= 0.3 ​​
    Given, 3 phages, So, probability of bacteria getting infected by 3 phages​= P(A) * P(B) * P(C) ​​​​​
    = 0.3 * 0.3 * 0.3 ​​​​​= 0.027

    Correct Option: D

    Probability of bacteria getting infected by a single bacteriophage= 0.3 i.e. P(A)= 0.3 ​​
    Given, 3 phages, So, probability of bacteria getting infected by 3 phages​= P(A) * P(B) * P(C) ​​​​​
    = 0.3 * 0.3 * 0.3 ​​​​​= 0.027



  1. In a chemostat operating under steady state, a bacterial culture can be grown at dilution rate higher than maximum growth rate by









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    Chemostat is operated by supplying an essential growth limiting nutrient at a constant rate with the result that the culture density and growth rate adjust themselves to the supply. ​​
    At steady state,
    dx / dt = 0 Therefore, μ = D ​​
    This equation shows that by simply varying the medium supply rate the growth rate can be varied.This equation holds true if μ eD or μ–D = positive. ​​
    Here, Dc = μmax, i.e. the critical dilution rate is defined as the lowest dilution rate at which washout occurs.
    ​​Thus, for a bacterial culture to grow at dilution rate higher than maximum growth rate, the partial cell recycling is needed under steady state condition. ​

    Correct Option: A

    Chemostat is operated by supplying an essential growth limiting nutrient at a constant rate with the result that the culture density and growth rate adjust themselves to the supply. ​​
    At steady state,
    dx / dt = 0 Therefore, μ = D ​​
    This equation shows that by simply varying the medium supply rate the growth rate can be varied.This equation holds true if μ eD or μ–D = positive. ​​
    Here, Dc = μmax, i.e. the critical dilution rate is defined as the lowest dilution rate at which washout occurs.
    ​​Thus, for a bacterial culture to grow at dilution rate higher than maximum growth rate, the partial cell recycling is needed under steady state condition. ​