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A bacterial culture with an approximate biomass composition of CH1.8O0.5N0.2 is grown aerobically on a defined medium containing glucose as the sole carbon source and ammonia being the nitrogen source. In this fermentation, biomass is formed with a yield coefficient of 0.35 gram dry cell weight per gram of glucose and acetate is produced
with a yield coefficient of 0.1 gram acetate per gram of glucose. The respiratory coefficient for the above culture will be
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- 0.90
- 0.95
- 1.00
- 1.05
Correct Option: B
| Yx/s = 0.35 g/g , YP/S = 0.1 | ||||
| g glucose | g glucose |
The respiratory coefficient
| Respiratory quotient = | ||
| Moles of CO2 consumed |
| = | = 1.01 | |
| 4.95 |
C6 H12 O6 + b NH3 + O2 → CH1.8O0.5 N0.2 + eH2O + f CO2
C : 6a = 1 + f ...(1)
H : 12a + 3b = 1.8 + 2e ...(2)
O : 6a + 2d = 0.5 + e + 2F ...(3)
b = 0.2
N : b = 0.2
∴ 12a = 1.2 + 2e
6a = 1 + F
Let if a = 1, i.e. F = 5
e = 5.4
d = 4.95
b = 0.2
a = 1
