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Biochemical Miscellaneous

  1. A culture of bacteria is infected with bacteriophage at a multiplicity of 0.3. The probability of a single cell infected with 3 phages is ​
    1. 0.9 ​
    2. 0.27 ​
    3. 0.009
    4. 0.027 ​
Correct Option: D

Probability of bacteria getting infected by a single bacteriophage= 0.3 i.e. P(A)= 0.3 ​​
Given, 3 phages, So, probability of bacteria getting infected by 3 phages​= P(A) * P(B) * P(C) ​​​​​
= 0.3 * 0.3 * 0.3 ​​​​​= 0.027



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