## Mathematical operation and symbol notation

#### Mathematical operation and symbol notation

1. Statement
L = M ≥ N;
M > P;
L < K.
Conclusions
I. K > P
II. N < K

1. Statement
L = M ≥ N;
M > P;
L < K ;
On combing both the statements, we get
P < L = M ≥ N < k
Conclusions
I. K > P         (false)
II. N < K       (true)

##### Correct Option: B

Statement
L = M ≥ N;
M > P;
L < K ;
On combing both the statements, we get
P < L = M ≥ N < k
Conclusions
I. K > P         (false)
II. N < K       (true)
Hence, only Conclusions II is definitely true.

1. Statement
U > A = I ≤ 0 < E
Conclusions
I. I ≤ E
II. 0 > U

1. Statement
U > A = I ≤ O < E
Conclusions
I. I ≤ E       (false)
II. O > U     (false)

##### Correct Option: D

Statement
U > A = I ≤ O < E
Conclusions
I. I ≤ E       (false)
II. O > U     (false)
Hence, neither Conclusion I nor II is definitely true.

1. Statement
A ≤ B < C ;
A ≥ D;
C ≤ F
Conclusions
I. D < C
II. F ≥ D

1. Statement
A ≤ B < C ;
A ≥ D ;
C ≤ F ;
On combining both the statements, we get
D ≤ A ≤ B < C ≤
Conclusions
I. D < C           (true)
II. F ≥ D       (false)
Hence, only conclusion I is definitely true.

##### Correct Option: A

Statement
A ≤ B < C ;
A ≥ D ;
C ≤ F ;
On combining both the statements, we get
D ≤ A ≤ B < C ≤
Conclusions
I. D < C           (true)
II. F ≥ D       (false)
Hence, only conclusion I is definitely true.

1. Statements
P < Q = R ≥ S ≥ T
Conclusions
I. T ≤ Q
II. R > P

1. Statements
P < Q = R ≥ S ≥ T
Conclusions
I. T ≤ Q
II. R > P

##### Correct Option: E

Statements
P < Q = R ≥ S ≥ T
Conclusions
I. T ≤ Q         (true)
II. R > P       (true)
Hence, both conclusions are definitely true.

1. Statements
F ≥ G = H;
G > J ≥ K
Conclusions
I. F ≥ K
II. K < H

1. Given that,
D > E ≤ F ............(i)
J < F ......................(ii)
On combining the statements (i) and (ii), we get
D > E ≤ F > J
Conclusions
I. D > J
II. E < J

##### Correct Option: D

Given that,
D > E ≤ F ............(i)
J < F ......................(ii)
On combining the statements (i) and (ii), we get
D > E ≤ F > J
Conclusions
I. D > J        (false)
II. E < J         (false)

So, it is clear that neither Conclusion I nor II is true