Engineering Mechanics Miscellaneous


Engineering Mechanics Miscellaneous

Engineering Mechanics

  1. A rigid rod (AB) of length L = √2 m is undergoing translational as well as rotational motion in the x-y plane (see the figure). The point A has the velocity V1 = i + 2j m/s. The end B is constrained to move only along the x direction.

    The magnitude of the velocity V2 (in m/s) at the end B is __________.









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    V1 = i + 2j
    |V1| = √2² + 1² = √5
    By drawing velocity diagram

    α = tan-12= 63.44
    1

    By applying sine rule
    5
    =
    V2
    sin 45sin 71.57

    ∴ V2 = 3 m/sec

    Correct Option: A

    V1 = i + 2j
    |V1| = √2² + 1² = √5
    By drawing velocity diagram

    α = tan-12= 63.44
    1

    By applying sine rule
    5
    =
    V2
    sin 45sin 71.57

    ∴ V2 = 3 m/sec


  1. A wheel of radius r rolls without slipping on a horizontal surface shown below. If the velocity of point P is 10 m/s in the horizontal direction, the magnitude of velocity of point Q (in m/s) is _____.









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    Vp = r ω = 10 m/s
    Vq = 2 r ω = 2 × 10 = 20 m/s

    Correct Option: A

    Vp = r ω = 10 m/s
    Vq = 2 r ω = 2 × 10 = 20 m/s



  1. A circular object of radius /rolls without slipping on a horizontal level floor with the center having velocity V. The velocity at the point of contact between the object and the floor is









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    NA

    Correct Option: A

    NA


  1. A straight rod length L(t), hinged at one end freely extensible at the other end, rotates through an angle θ(t) about the hinge. At time t, L(t) = 1 m, L(t) = 1 m/s, θ(t) = π/4 rad and θ (t) = 1 rad/s. The magnitude of the velocity at the other end of the rod is









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    v = √1² + 1² = √2 m / s

    Correct Option: B


    v = √1² + 1² = √2 m / s



  1. A shell is fired from a cannon. At the instant the shell is just about to leave the barrel, its velocity relative to the barrel is 3 m/s, while the barrel is swinging upwards with a constant angular velocity of 2 rad/s. The magnitude of the absolute velocity of the shell is









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    ωr = 2 × 2 = 4m/sec
    υnet = √3² + 4² = 5 m / s

    Correct Option: C


    ωr = 2 × 2 = 4m/sec
    υnet = √3² + 4² = 5 m / s