Engineering Mechanics Miscellaneous


Engineering Mechanics Miscellaneous

Engineering Mechanics

  1. The figure shows a pair of pin-jointed gripper tongs holding an object weighing 2000 N. The coefficient of friction μ at the gripping surface is 0.1. XX is the line of action of the input force and YY is the line of application of gripping force. If the pin- joint is assumed to be friction less, the magnitude of force F required to hold the weight is









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    For vertical equilibrium 2Fr = 2000 N
    Fr = 1000 N
    Fr = m . RN
    1000 = 0.1 RN

    RN =
    1000
    = 10000 N.
    0.1

    Taking moment about P, we have

    0.3 × F = RN × 0.150
    0.3F = 10000 × 0.150
    F =
    1000 × 0.15
    0.3

    =
    10,000 × 15
    = 5000 N.
    30

    Correct Option: D


    For vertical equilibrium 2Fr = 2000 N
    Fr = 1000 N
    Fr = m . RN
    1000 = 0.1 RN

    RN =
    1000
    = 10000 N.
    0.1

    Taking moment about P, we have

    0.3 × F = RN × 0.150
    0.3F = 10000 × 0.150
    F =
    1000 × 0.15
    0.3

    =
    10,000 × 15
    = 5000 N.
    30


  1. The ratio of tension on the tight side to that of the slack ride in a flat belt drive is









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    T1
    = eμθ
    T1

    Correct Option: B

    T1
    = eμθ
    T1