Problem Based on ages
- A man is 3 years older than his wife and four times as old as his son. If the son becomes 15 years old after 3 years, then what is the present age of the wife?
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Suppose age of son = P years
Age of the man = 4P years
Age of man’s wife = 4P – 3 years
According to the question,
After 3 years, age of son + 3 years = 15
P + 3 = 15
∴ P = 15 – 3 = 12 yearsCorrect Option: D
Suppose age of son = P years
Age of the man = 4P years
Age of man’s wife = 4P – 3 years
According to the question,
After 3 years, age of son + 3 years = 15
P + 3 = 15
∴ P = 15 – 3 = 12 years
Now, age of wife = 4P – 3 years
age of wife = 4 × 12 – 3 years
age of wife = 48 – 3 years
age of wife = 45 years
- Anil is as much younger to Vivek as he is older to Tarun. If the total of the ages of Vivek and Tarun is 48 years, how old is Anil?
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Suppose, Anil (A) is P years younger to Vivek (V).
Now, A = V – P .......( ⅰ )
A = T + P .......( ⅱ )
On adding eq.( ⅰ ) and ( ⅱ ) , we get
A + A = V – P + T + P
the total of the ages of Vivek and Tarun is 48 years
⇒ 2A = V + T = 48Correct Option: C
Suppose, Anil (A) is P years younger to Vivek (V).
Now, A = V – P .......( ⅰ )
A = T + P .......( ⅱ )
On adding eq.( ⅰ ) and ( ⅱ ) , we get
A + A = V – P + T + P
the total of the ages of Vivek and Tarun is 48 years
⇒ 2A = V + T = 48∴ A = 48 = 24 years 2
- The age of the father 4 years ago was 8 times the age of his son. At present, the father’s age is 4 times that of his son. Find the present age of son.
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Suppose, the present age of son be P years.
Therefore, the present age of father = 4P years
According to the question,
4 years ago , 8 ( the present age of son – 4 years ) = ( the present age of father – 4 )
4 years ago , 8 (P – 4) = 4P – 4
⇒ 8P – 32 = 4P – 4
⇒ 8P – 4P = 32 – 4
⇒ 4P = 28Correct Option: B
Suppose, the present age of son be P years.
Therefore, the present age of father = 4P years
According to the question,
4 years ago , 8 ( the present age of son – 4 years ) = ( the present age of father – 4 )
4 years ago , 8 (P – 4) = 4P – 4
⇒ 8P – 32 = 4P – 4
⇒ 8P – 4P = 32 – 4
⇒ 4P = 28∴ P = 28 = 7 4
Hence ,the present age of son be 7 years.
- 12 year old Sami is three times as old as his brother Vinay. How old will Sami be when he is twice as old as Vinay?
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Age of Sami = 12 years
Age of vinay = 12 = 4 years 3 Correct Option: D
Age of Sami = 12 years
Age of vinay = 12 = 4 years 3
After 4 years Age of Sami = 16 years
Age of Vinay = 8 years
- The age of Dr. Pandey is four times the age of his son. After 10 years, the age of Dr. Pandey will be twice the age of his son. The present age of Dr. Pandey’s son is :
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Suppose the present age of son = P years
Therefore, the present age of Dr. Pandey = 4P years
According to question ,
After 10 years, ( The present age of Dr. Pandey + 10 yaers ) = 2 ( the present age of son + 10 years )
4P + 10 = 2 (P + 10)
⇒ 4P + 10 = 2P + 20
⇒ 4P – 2P = 20 – 10
⇒ 2P = 10Correct Option: B
Suppose the present age of son = P years
Therefore, the present age of Dr. Pandey = 4P years
According to question ,
After 10 years, ( The present age of Dr. Pandey + 10 yaers ) = 2 ( the present age of son + 10 years )
4P + 10 = 2 (P + 10)
⇒ 4P + 10 = 2P + 20
⇒ 4P – 2P = 20 – 10
&rArr 2P = 10∴ P = 10 = 5 years 2
Therefore , The present age of Dr. Pandey’s son is 5 years .
