Problem Based on ages
- 5 years ago, the average age of Ram and Shyam was 20 years. Now, the average age of Ram, Shyam and Mohan is 30 years. What will be Mohan's age 10 years hence?
-
View Hint View Answer Discuss in Forum
Let us assume the present age of Ram R, Shyam S and Mohan M.
Correct Option: A
Let us assume the present age of Ram R, Shyam S and Mohan M.
5 years ago, Ram age = R - 5
5 years ago, Shyam age = S - 5
5 years ago, Mohan age = M - 5
According to question,
5 years ago, the average age of Ram and Shyam was 20 years,
(5 years ago, Ram age + 5 years ago, Shyam age) /2 = 20
(R - 5 + S - 5 )/2 = 20
R + S = 40 + 10 = 50 ................(1)
Now Again according to question,
Now , the average age of Ram, Shyam and Mohan is 30 years
(R + S + M)/3 = 30
R + S + M = 90
Pu the value of R + S from equation (1)
50 + M = 90
M = 90 - 50 = 40
The present age of Mohan = 40 years
10 years hence, the age of Mohan = 40 + 10 = 50 years
- The ratio of the present ages of Suresh and his daughter is 2 : 1. Six years hence, the ratio of their ages would be 23 : 13. Find the present age of Suresh?
-
View Hint View Answer Discuss in Forum
Let us assume the present ages of Suresh and his daughter be 2x and x years respectively.
Correct Option: B
Let the present ages of Suresh and his daughter be 2x and x years respectively; then
According to question,
Six years hence, the ratio of their ages would be 23 : 13
(2x + 6) / (x + 6) = 23/13
⇒ (2x + 6) 13 = 23 (x + 6)
⇒ 26x + 78 = 23x + 138
⇒ 3x = 60
∴ x = 20
Hence, present age of Suresh = 2 x 10 = 40 years
- The present age of father is 34 years more than that of his son. 12 years ago, father's age was 18 times the age of his son. The present age of son in years is :
-
View Hint View Answer Discuss in Forum
Let us assume the present ages of son be Y then his father present age will be Y + 34 years.
Correct Option: B
Let us assume the present ages of son be Y then his father present age will be Y + 34 years. then
12 years ago, father's age = Y + 34 -12
12 years ago, Son's age = Y - 12
Now according to question,
12 years ago, father's age was 18 times the age of his son. then
18( Y - 12 ) = Y + 34 - 12
⇒ 18Y - 216 = Y + 22
⇒ 17Y = 238
∴ Y = 14
Hence, present age of his son = 14 years.
- The ratio of the ages of two persons is 4 : 7 and age of then is more than other by 30 years. The sum of their ages in years is:
-
View Hint View Answer Discuss in Forum
Let the present ages of two person be 4x and 7x years respectively;
Correct Option: B
Let the present ages of two person be 4x and 7x years respectively; then according to question,
7x = 30 + 4x
⇒ 3x = 30
∴ x = 10
Hence, sum of their ages = 4x + 7x = 11x = 11 x 10 = 110 years
- A father is older than his first son by 30 years, the first son is older than the second son by 10 years. If the sum of their ages be 95 years, find the age of father.
-
View Hint View Answer Discuss in Forum
Let us assume the age of second son be Y, then age of first son will be Y + 10 and age of father will be (Y + 10 + 30) years respectively;
Correct Option: C
Let us assume the age of second son be Y, then age of first son will be Y + 10 and age of father will be (Y + 10 + 30) years respectively;
then according to question,
sum of their ages be 95 years.
x + x + 10 + x + 10 + 30 = 95
⇒ 3x = 95 - 50
⇒ 3x = 45
∴ x = 15
age of the father = x + 10 + 30
Hence, age of the father = 15 + 10 + 30 = 55 years.