Problem Based on ages

Problem Based on ages

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  1. The difference between a mother’s age and the sum of her two daughters’ age is 6. The average age of two daughters is 22. What is the age of mother?








  1. View Hint View Answer Discuss in Forum

    According to question ,
    Mother’s age - Sum of her two daughters’ age = 6.
    The average age of two daughters = 22
    Total age of two daughters = 22 × 2 = 44 years
    ∴ The age of their mother = Total age of two daughters + 6 years

    Correct Option: D

    According to question ,
    Mother’s age - Sum of her two daughters’ age = 6.
    The average age of two daughters = 22
    Total age of two daughters = 22 × 2 = 44 years
    ∴ The age of their mother = Total age of two daughters + 6 years
    The age of their mother = 44 + 6 = 50 years

  1. A man was 32 years of age when he had his first son. His wife was 35 years of age when his son attained the age of 7 years. The difference in age between the man and his wife is








  1. View Hint View Answer Discuss in Forum

    According to question ,
    Age of his wife = 35 years
    Age of his son = 7 years and Age of man = 32 years
    At the birth of son, The age of mother = Age of his wife - Age of his son = 35 – 7 = 28 years
    Difference in age = Age of man - age of mother

    Correct Option: D

    According to question ,
    Age of his wife = 35 years
    Age of his son = 7 years and Age of man = 32 years
    At the birth of son, The age of mother = Age of his wife - Age of his son = 35 – 7 = 28 years
    Difference in age = Age of man - age of mother = 32 – 28 = 4 years

  1. Hema was twice as old as Geetha 10 years ago. How old is Geetha today if Hema will be 40 years old 10 years hence?








  1. View Hint View Answer Discuss in Forum

    Suppose that the present age of Geetha is P years
    10 years after , age of Hema = 40 years
    Present age of Hema = 40 – 10 = 30 years
    According to question
    10 years ago , 2( present age of Geetha – 10 years ) = present age of Hema – 10
    ⇒ 2( P – 10 ) = 30 – 10
    ⇒ 2P – 20 = 20
    ⇒ 2P = 20 + 20 = 40

    Correct Option: B

    Suppose that the present age of Geetha is P years
    10 years after , age of Hema = 40 years
    Present age of Hema = 40 – 10 = 30 years
    According to question
    10 years ago , 2( present age of Geetha – 10 years ) = present age of Hema – 10
    ⇒ 2( P – 10 ) = 30 – 10
    ⇒ 2P – 20 = 20
    ⇒ 2P = 20 + 20 = 40

    ∴ P =
    40
    		 = 20 years
    2

    Hence ,the present age of Geetha is 20 years .

  1. Naresh’s age is 4 years less than twice the age of his brother. Which of the following represents the equation to find his age?








  1. View Hint View Answer Discuss in Forum

    Suppose the age of Naresh’s brother = P years
    According to question ,
    ∴ Age of Naresh = 2 × age of Naresh’s brother – 4

    Correct Option: D

    Suppose the age of Naresh’s brother = P years
    According to question ,
    ∴ Age of Naresh = 2 × age of Naresh’s brother – 4
    Therefore , Age of Naresh = 2P – 4