Mathematical operation and symbol notation
Direction: In the following questions, which one of the four interchanges in signs and numbers would make the given equation correct?
 (3 ÷ 4) + 2 = 2

 + and ÷, 2 and 4
 + and , 3 and 4
 + and ÷, 2 and 3
 None of the above

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On interchanging signs '+' to '÷' and 2 to 3
(2 + 4) ÷ 3 = 2
⇒ 6 ÷ 3 = 2 ⇒ 2 = 2Correct Option: C
On interchanging signs '+' to '÷' and 2 to 3
(2 + 4) ÷ 3 = 2
⇒ 6 ÷ 3 = 2 ⇒ 2 = 2
 (6 ÷ 2) x 3 = 0

 x to , 2 and 6
 ÷ and x, 2 and 3
 x to , 2 and 3
 ÷ and x, 2 and 6

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On interchanging signs 'x' to '' and 2 to 3
(6 ÷ 3)  2 = 0
⇒ 2  2 = 0
⇒ 0 = 0Correct Option: C
On interchanging signs 'x' to '' and 2 to 3
(6 ÷ 3)  2 = 0
⇒ 2  2 = 0
⇒ 0 = 0
Direction: Study the following information carefully and answer the given questions. If '+' is coded as 'π' , 'x' is coded as '≠' , '÷' is coded as '$' and '' is coded as Δ, then what is the value of the following ?
 2 ≠ 7 Δ 4

 9
 3
 13
 10

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Given, 2 ≠ 7 Δ 4
After interchanging the signs,
2 x 7  4
Apply the BODMAS RuleCorrect Option: D
Given, 2 ≠ 7 Δ 4
After interchanging the signs,
2 x 7  4
Apply the BODMAS Rule
2 x 7  4 = 14  4 = 10.
 17 ≠ 12 $ 3

 98
 87
 75
 68

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Given, 17 ≠ 12 $ 3
After interchanging the sign,
17 x 12 ÷ 3
Apply the BODMAS Rule.Correct Option: D
Given, 17 ≠ 12 $ 3
After interchanging the sign,
17 x 12 ÷ 3
Apply the BODMAS Rule
= 17 x 4 = 68
 72 π 27 Δ 99

 65
 52
 47
 0

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72 π 27 Δ 99
After interchanging the signs,
72 + 27  99
Apply the BODMAS Rule.Correct Option: D
72 π 27 Δ 99
After interchanging the signs,
72 + 27  99
Apply the BODMAS Rule.
= 99  99 = 0