Bar graph
Direction: Study the following graph carefully to answer the questions that follow : Distance (in Km) traveled by 5 different trucks in a day.
- What is the average distance traveled by all the trucks together?
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Required Average distance covered by all the trucks = Total distance covered by all the trucks Total number of the trucks
Correct Option: D
Given in the bar graph :-
Distance traveled by Trucks A = 475 , B = 350, C = 550, D = 425, E = 575,
Total distance covered by all the trucks = 475 + 350 + 550 + 425 + 575 = 2375 Km
Total number of the trucks = 5Required Average distance covered by all the trucks = Total distance covered by all the trucks Total number of the trucks Required Average distance covered by all the trucks = 2375 = 475 5
- The distance travelled by Truck E is approximately what percent of the total distance travelled by Track B and C together?
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Required percentage = Total distance covered by E x 100 % Total distance covered by B and C together
Correct Option: D
As per given graph , we can see that
Total distance covered by E = 575 Km , Total distance covered by B and C together = 350 + 550 = 900 KmRequired percentage = Total distance covered by E x 100 % Total distance covered by B and C together = 575 x 100 ≈ 64% ≈ 62 % 900
- What is the ratio of the distance traveled by Truck A to the distance traveled by Truck D?
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Required ratio = The distance traveled by Truck A : The distance traveled by Truck D
Correct Option: C
As per given above graph , we have
The distance traveled by Truck A = 475
The distance traveled by Truck Truck D = 425
Required ratio = The distance traveled by Truck A : The distance traveled by Truck D
Required ratio = 475 : 425 = 19 : 17
Direction: Study the following graph carefully to answer these questions. Number of students in College A and College B over the years.
- What is the approximate percentage rise in the number of students of College B from 2005 to 2006?
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percentage rise in the number of students of College B from 2005 to 2006
= Total increase in the number of students of College B from 2005 to 2006 x 100 % Number of students of College B from 2005
Correct Option: A
Given :- Number of students of College B in year 2005 = 65000
Number of students of College B in year 2006 = 70000
Total increase in the number of students of College B from 2005 to 2006 = Number of students of College B in year 2006 - Number of students of College B in year 2005
= 70000 - 65000 = 5000
∴ percentage rise in the number of students of College B from 2005 to 2006= Total increase in the number of students of College B from 2005 to 2006 x 100 % Number of students of College B from 2005 = 5000 x 100 % = 7.69% ≈ 8% 65000
- For which college(s) and in which year was the percent rise in number of students from the previous year the highest?
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Percentage rise in number of students from college A in 2004
= total increase in number of students in College A from years 2004 to 2003 x 100% total number of students in College A in year 2004
Percentage rise in number of students from college B in 2004= total increase in number of students in College B from years 2004 to 2003 x 100% total number of students in College B in year 2004 Correct Option: C
From above given graph , we can see that
Number of students from college A in 2003 = 20 × 103
Number of students from college A in 2004 = 40 × 103
Total increase in number of students in College A from 2004 to 2003 = 40 - 20 = 20 × 103
Percentage rise in number of students from college A in 2004= total increase in number of students in College A from years 2004 to 2003 x 100% total number of students in College A in year 2004 = 20 × 103 x 100 = 100 % 20 × 103
And Number of students from college B in 2003 = 30 × 103
Number of students from college B in 2004 = 60 × 103
total increase in number of students in College B from years 2004 to 2003 = 60 - 30 = 30 × 103
Similarly,
Percentage rise in number of students from college B in 2004= total increase in number of students in College B from years 2004 to 2003 x 100% total number of students in College B in year 2004 = 30 × 103 x 100 = 100 % 30 × 103