Control system miscellaneous
- In the given system, (Q. 56) if a = 0.1, then steady state error to unity ramp input will be______ .
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G(s) = 8 s2 + (2 + 8a)s = 8 s2 + 2.8 s ∴ ess = 1 = 2.8 = 0.35 Kv 8
Correct Option: A
G(s) = 8 s2 + (2 + 8a)s = 8 s2 + 2.8 s ∴ ess = 1 = 2.8 = 0.35 Kv 8
- In the system shown in the figure, r(t) = sin ωt
The steady-stat e response c(t) will exhibit a resonance peak at a frequency of_______ rad/sec
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∴ C(s) = 16 = 8 s(s + 4) R(s) 1 + 16 × 1 16 + s(s + 4) s(s + 4) C(jω) = 16 = 16 R(jω) 16 + jω(jω + 4) 16 - ω² + 4jω = 16 ∠ -tan-1 4ω √(16 - ω)² + (4ω)² (16 - ω²)
For resonance to occurd √(16 - ω)² + (4ω)² = 0 dω
F(ω) = (16 - ω²)² + (4 ω)²
= ω4 + 256 - 32 ω² + 16ω²
= ω4 - 16 ω² + 256∴ dF(ω) = 4ω3 - 32 ω = 0 dω
⇒ ω = √8 = 2 √2 rad / secCorrect Option: A
∴ C(s) = 16 = 8 s(s + 4) R(s) 1 + 16 × 1 16 + s(s + 4) s(s + 4) C(jω) = 16 = 16 R(jω) 16 + jω(jω + 4) 16 - ω² + 4jω = 16 ∠ -tan-1 4ω √(16 - ω)² + (4ω)² (16 - ω²)
For resonance to occurd √(16 - ω)² + (4ω)² = 0 dω
F(ω) = (16 - ω²)² + (4 ω)²
= ω4 + 256 - 32 ω² + 16ω²
= ω4 - 16 ω² + 256∴ dF(ω) = 4ω3 - 32 ω = 0 dω
⇒ ω = √8 = 2 √2 rad / sec
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The unit step error coefficient of a system G(s) = 1 (s + 6)(s + 1)
with unity feedback is _______
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Correct Option: C
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The value of k for a unity feedback system with G(s) = k s(1 + s)
to have a peak overshoot of 50% is _______
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T(s) = k s2 + s + k
2 ξ ωn = 1 , ωn = √kξ = 0.5 √k Mp = 0.50 = exp -π ξ √1 - ξ² ⇒ 0.5 = 0.16 √1 - ξ²
ξ = 0.15
k = 5.3Correct Option: B
T(s) = k s2 + s + k
2 ξ ωn = 1 , ωn = √kξ = 0.5 √k Mp = 0.50 = exp -π ξ √1 - ξ² ⇒ 0.5 = 0.16 √1 - ξ²
ξ = 0.15
k = 5.3
- A unity-feedback control system has the open-loop transfer function
G(s) = 4(1 + 2s) s2 (s + 2)
If input to the system is a unit ramp, then steadystate error will be_______
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Open loop transfer function = 4(1 + 2s) s2 (s + 2)
unit ramp
Type 2.
Steady state error = 0Correct Option: A
Open loop transfer function = 4(1 + 2s) s2 (s + 2)
unit ramp
Type 2.
Steady state error = 0