Computer networks miscellaneous

Computer networks miscellaneous

Easy Questions

Computer Networks

Computer networks miscellaneous
  1. Match the List I with List II and select the correct answer by using the codes given below the lists.









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    SMTP (Simple mail transfer Protocol) is application layer based. BGP is network layer based. TCP (Transport Control Protocol) is transport layer based. PPP (Point to Point protocol) is data link layer based protocol. Hence (b) is correct option.

    Correct Option: B

    SMTP (Simple mail transfer Protocol) is application layer based. BGP is network layer based. TCP (Transport Control Protocol) is transport layer based. PPP (Point to Point protocol) is data link layer based protocol. Hence (b) is correct option.

  1. Match the List I with list II and select the correct answer by using the codes given below the lists.









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    Transport layer functions as a communication layer for any kind of end to end communication, creation of sockets. Network layer routes the data from one node to other, till it reach to destination. Datalink layer ensures reliable data transfer by error correction, duplication check ordered delivery etc.

    Correct Option: A

    Transport layer functions as a communication layer for any kind of end to end communication, creation of sockets. Network layer routes the data from one node to other, till it reach to destination. Datalink layer ensures reliable data transfer by error correction, duplication check ordered delivery etc.

  1. Which one of the following statements is NOT correct about HTTP cookies?








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    Cookies are not Piece of code they are just strings typically in the form of key value pairs.

    Correct Option: A


    Cookies are not Piece of code they are just strings typically in the form of key value pairs.

Direction: Frames of 1000 bits are sent over a 106 bps duplex link between two hosts. The propagation time is 25 ms. Frames are to be transmitted into this link to maximally pack them in transit (within the link).

  1. What is the minimum number of bits l that will be required to represent the sequence numbers distinctly? Assume that no time gap need to be given between transmission of two frames.








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    Pulse rate =
    Number of bits
    		 =
    1000
    		 = 4 × 104
    Time taken25 × 10-3

    Now, Bit rate = Pulse rate × 21
    21 = 25 ⇒ I = 5

    Correct Option: D

    Pulse rate =
    Number of bits
    		 =
    1000
    		 = 4 × 104
    Time taken25 × 10-3

    Now, Bit rate = Pulse rate × 21
    21 = 25 ⇒ I = 5

  1. Suppose that the sliding window protocol is used with the sender window size of 21, where 1 is the number of its identified in the earlier part and acknowledgments are always piggy backed. After sending 21 frames, what is the minimum time, the sender will have to wait before starting transmission of the next frame? (Identify the closest choice ignoring the frame processing time.)








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    Time taken to send 10^6 bits = 1 s
    Now, as 1 frame = 1000 bits
    Time taken to send 2^5 frames = 32 ms
    Also, Time taken for first frame to be acknowledged = 25 × 2 = 50 ms
    Hence, the waiting time = 50 – 32 = 18 ms

    Correct Option: B

    Time taken to send 10^6 bits = 1 s
    Now, as 1 frame = 1000 bits
    Time taken to send 2^5 frames = 32 ms
    Also, Time taken for first frame to be acknowledged = 25 × 2 = 50 ms
    Hence, the waiting time = 50 – 32 = 18 ms