Architecture and Planning Miscellaneous-topic

Architecture and Planning Miscellaneous-topic

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Architecture and Planning Miscellaneous

Architecture and Planning Miscellaneous-topic

Direction: A standpipe system in a 39 m tall building has a rooftop reservoir for fire fighting containing 1/2 hour water supply.

  1. The volume of water (in cubic meter) required for the reservoir is








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    NA

    Correct Option: B

    NA

Direction: A plot of land is to be developed as a residential neighborhood. The key development conditions and project requirements are given below
Plot area: 1.25 Hectares
Maximum pemissible ground coverage: 30%
Density of population: 800 ppHa
Maximum pemissible FAR: 350
Maximum permissible height: 45 m
Average household size: 3.55

  1. With the above data, the covered area of each flat (in sq. m) under L.I.G., M.l.G. and H.I .G. respectively are








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    A (is the closest)
    Covered Area for each Flat = Total Built-Upof the Flat Type/No. of units in the Flat Type

    Correct Option: A

    A (is the closest)
    Covered Area for each Flat = Total Built-Upof the Flat Type/No. of units in the Flat Type

  1. The total number of dwelling units under L.I.G., M.I.G. and H.I.G. respectively are









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    The question is not well-specified. C seems to be the closest answer.
    Density of Population = 800 ppH (Assuming it to be Residential-density of Dwelling Units)
    Plot Area = 1.25 hectares
    Average household Size = 3.55
    Let n be the no. of Dwelling Units Net area of Dwelling Units
    Total built up of all units = 4480 + 18600 + 14200
    = 37280 sq m = 3.7 hectares
    FAR × Total Plot Area of D.U = Total Built-up
    3.50 × Total Plot Area of D.U = 37,280 sq m
    Total Plot Area of D.U = 37,280/3.50 = 10651 sq m = 1.065 hectares
    Density = Total Population /Total Area
    Density = No. of Dwelling Units × Avg Household size/Total Area under Dwelling units
    880 = (n × 3.55)/1.065 DU = 264
    Total no. of Dwelling units as 264 for further calculations,

    Correct Option: C

    The question is not well-specified. C seems to be the closest answer.
    Density of Population = 800 ppH (Assuming it to be Residential-density of Dwelling Units)
    Plot Area = 1.25 hectares
    Average household Size = 3.55
    Let n be the no. of Dwelling Units Net area of Dwelling Units
    Total built up of all units = 4480 + 18600 + 14200
    = 37280 sq m = 3.7 hectares
    FAR × Total Plot Area of D.U = Total Built-up
    3.50 × Total Plot Area of D.U = 37,280 sq m
    Total Plot Area of D.U = 37,280/3.50 = 10651 sq m = 1.065 hectares
    Density = Total Population /Total Area
    Density = No. of Dwelling Units × Avg Household size/Total Area under Dwelling units
    880 = (n × 3.55)/1.065 DU = 264
    Total no. of Dwelling units as 264 for further calculations,

Direction: A simply supported beam PQ is subjected to a load of 100 kN through a rigid link at the centre of the beam as shown in the figure below

  1. Bending moment diagram for the above beam is








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    B.M @ P = 0
    B.M @ Q = 0
    B.M @ mid-point = 5 kN-m and changing

    Correct Option: D


    B.M @ P = 0
    B.M @ Q = 0
    B.M @ mid-point = 5 kN-m and changing

  1. Correct shear force diagram for the beam is








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    Taking moment about Q of all the forces and equate it to zero.
    RP x 10 = 10 ; RP = 1 kN(↑) and RQ = 1 kN (↓)

    Correct Option: A


    Taking moment about Q of all the forces and equate it to zero.
    RP x 10 = 10 ; RP = 1 kN(↑) and RQ = 1 kN (↓)