Architecture and Planning Miscellaneous-topic Difficult Questions and Answers | Page - 36

Architecture and Planning Miscellaneous-topic

Match the photometric quantities in Group-I with their respective units in Group-II
Group I Group II
P. Illuminance 1. Candela
Q. Luminous Intensity 2. Candela/sqm
R. Luminance 3. Lumens/sqm
S. Luminous Efficacy 4. Lumens/watt
5. Lumens

1. P-3, Q-2, R-5, S-4
1. P-5, Q-4, R-2, S-1
1. P-5, Q-1, R-2, S-3
1. P-3, Q-1, R-2, S-4

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Correct Option: D

Associate the fire safety requirements for high rise buildings in Group-I with corresponding standards of the National Building Code of India 2016 in Group-II
Group I Group II
P. Minimum Refuge area 1. 12.5 sqm/person
Q. Maximum Travel distance 2. 2.0 m
R. Maximum Occupant load 3. 0.3 sqm/person
S. Minimum Stair case width 4. 12.0 ton
5. 30.0 m

1. P-4, Q-1, R-5, S-2
1. P-3, Q-5, R-4, S-1
1. P-3, Q-5, R-1, S-2
1. P-4, Q-5, R-1, S-3

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P. Minimum Refuge area – 0.3 sqm/person
Q. Maximum Travel distance – 30.0 m
R. Maximum Occupant load – 12.5 sqm/person
S .Minimum Stair case width – 2.0 m

Correct Option: C

P. Minimum Refuge area – 0.3 sqm/person
Q. Maximum Travel distance – 30.0 m
R. Maximum Occupant load – 12.5 sqm/person
S .Minimum Stair case width – 2.0 m

Match the planning documents in Group-I with their respective government schemes in GroupII

Group I	Group II
P. Integrated Cluster Action Plan	1. NULM
Q. Service Level Improvement Plan	2. Make in India
R. Housing for All Plan of Action	3. RuRBAN mission
S. City Livelihood Centre Development Plan	4. PMAY
	5. AMRUT

1. P-4, Q-1, R-5, S-2
1. P-3, Q-5, R-4, S-2
1. P-5, Q-1, R-4, S-3
1. P-3, Q-5, R-4, S-1

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Correct Option: D

A 25 storeyed building has 5 lifts. The resulting waiting time is 35 sec and ‘Return Travel Time’ is 175 sec. The number of lifts required for reducing waiting time to 25 sec, without increasing the lift speed, is _______________

1. 7.0 to 7.0
1. 6.0 to 7.0
1. 9.0 to 7.0
1. 4.0 to 7.0

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7.0 to 7.0
Resulting waiting time (T) =
Return travel time RT of Lits.
No.

Here, Expected Resulting wating time (T) = 25 sec.
Return travel time (RT) = 175 Sec.
Thus, No. of Lits required = RT = 175 = 7
T 25

Correct Option: A

7.0 to 7.0
Resulting waiting time (T) =
Return travel time RT of Lits.
No.

Here, Expected Resulting wating time (T) = 25 sec.
Return travel time (RT) = 175 Sec.
Thus, No. of Lits required = RT = 175 = 7
T 25

A room of 3m × 3m × 3m has a reverberation time of 0.8 sec. Using Sabine’s method, the total absorption in the room is _____________ sabin (up to one decimal place).

1. 2.3 to 9.7
1. 4.3 to 6.7
1. 5.3 to 5.7
1. 6.3 to 5.7

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5.3 to 5.7
RT₆₀ is the reverberation time (to drop 60 dB)
V is the volume of the room
c₂₀ is the speed of sound at 20° C (room temperature)
Sa is the total absorption in sabins.
RT₆₀ = 24(In 10) V
c₂₀Sa

0.8 = 24 × (In 10) × 27
343Sa

Sa = 5.43 sabin

Correct Option: C

5.3 to 5.7
RT₆₀ is the reverberation time (to drop 60 dB)
V is the volume of the room
c₂₀ is the speed of sound at 20° C (room temperature)
Sa is the total absorption in sabins.
RT₆₀ = 24(In 10) V
c₂₀Sa

0.8 = 24 × (In 10) × 27
343Sa

Sa = 5.43 sabin