Analog circuits miscellaneous
-  An amplifier has an open loop gain of 100, an input impedance of 1kΩ, and an out put impedance of 100 Ω. If a feedback network with a feedback factor of 0.99 is connected in a voltage series feedback mode then new input and output impedances are
 (a)
 (b)
 (c)
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                        View Hint View Answer Discuss in Forum Zif = Zi (1 + βA) = 1 k (1 + 100 × 0.99) = 100 kΩ Zof = Z0 = 100 = 1 Ω 1 + βA 100 
 Correct Option: CZif = Zi (1 + βA) = 1 k (1 + 100 × 0.99) = 100 kΩ Zof = Z0 = 100 = 1 Ω 1 + βA 100 
 
-  In the circuit shown in the given figure, the type of feedback used is 
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                        View Hint View Answer Discuss in Forum NA Correct Option: BNA 
-  In the single-stage transistor amplifier circuit shown in the given figure, if capacitor CE is removed, then, ac small-signal midband voltage gain of the amplifier 
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                        View Hint View Answer Discuss in Forum  
 With CE, voltage gainAυ = - -hfeRL hie + (1 + hfe)RE 
 If RE by passed with capacitor CE, AV will increase Hence, after removing CE mid band voltage gain decreases.Correct Option: B 
 With CE, voltage gainAυ = - -hfeRL hie + (1 + hfe)RE 
 If RE by passed with capacitor CE, AV will increase Hence, after removing CE mid band voltage gain decreases.
-  If an input signal with non-zero dc component is applied to a low pass RC network, then dc component in the output will be 
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                        View Hint View Answer Discuss in Forum NA Correct Option: ANA 
-  A junction transistor operating at room temperature with IC = 2 mA, where (kT / q) = 20 mV and β = 100. The values of parameter gm in mhos and rπ in ohm respectively are
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                        View Hint View Answer Discuss in Forum gm = IC = 2 = 0.08 VT 25 rm = β = 100 = 1250 gm 0.08 Correct Option: Bgm = IC = 2 = 0.08 VT 25 rm = β = 100 = 1250 gm 0.08 
 
	