Problem Based on ages

Problem Based on ages

Easy Questions
Moderate Questions
Difficult Questions

Verbal Reasoning

Eligibility Test
Logical order of words
Mathematical operation and symbol notation
Clock and calender
Problem Based on ages
Alphabet Test
Input Output
Linear Arrangement
Matrix Arrangement
Circular Arrangement
Logical Connectivity
Games And Tournament
Analogy
Classification
Number Series
Letter and Symbol Series
Coding Decoding
Sequencing and Formation
Direction and Distance
Sitting Arrangement
Blood Relations
Logical Venn Diagram
Cubes
Logical Problems
Theme Detection
Logical Deduction
Matching Definitions
Making Judgments
Logical Games
Verification of Truth/Lie of Statements
Routes and Networks
Time Sequence
Ranking Test
Inserting and Missing Character
Grid and Matrices
Syllogism
Statement and Argument
Statement and Assumption
Statement and Courses of Action
Statement and Conclusion
Cause and Effect
Grouping and Team Formation
Assertion and Reason
Situation Reaction Test
  1. The average weight of 8 persons of a family is increased by 1 kg when one of the members whose weight is 60 kg is replaced by a new person. The weight of the new person (in kg) is








  1. View Hint View Answer Discuss in Forum

    Here , n = 8 , Weight of replaced person = 60 kg and increase in Average = 1 kg
    Using formula ,
    ∴ Weight of new person = Weight of replaced person + n × increase in Average

    Correct Option: B

    Here , n = 8 , Weight of replaced person = 60 kg and increase in Average = 1 kg
    Using formula ,
    ∴ Weight of new person = Weight of replaced person + n × increase in Average
    Weight of new person = 60 + 8 × 1 = 68 kg

  1. At present a father’s age is 30 years more than that of his only son. What was his age when the son was born?








  1. View Hint View Answer Discuss in Forum

    Suppose the age of son at present = P years
    ∴ Present age of the father = Present age of son + 30 years
    Present age of the father = P + 30 years

    Correct Option: B

    Suppose the age of son at present = P years
    ∴ Present age of the father = Present age of son + 30 years
    Present age of the father = P + 30 years
    Age of father at the birth of his son = Present age of the father - Present age of son = ( P + 30 ) – P = 30 years

  1. The average age of 19 boys in a class is 21 years. If the teacher’s age is included, the average increases to 22 years. What is the teacher’s age?








  1. View Hint View Answer Discuss in Forum

    Given that :- The average age of 19 boys in a class = 21 years
    Total age of 19 boys = 19 × 21 = 399 years
    The average age of 19 boys and teacher = 22 years
    Total age of 19 boys and teacher = 20 × 22 = 440 years

    Correct Option: B

    Given that :- The average age of 19 boys in a class = 21 years
    Total age of 19 boys = 19 × 21 = 399 years
    The average age of 19 boys and teacher = 22 years
    Total age of 19 boys and teacher = 20 × 22 = 440 years
    ∴Teacher’s age = Total age of 19 boys and teacher - Total age of 19 boys
    Teacher’s age = 440 – 399 = 41 years
    Hence , the age of teacher is 41 years .

  1. 10 years ago, average age of A and B was 20 years. Average age of A, B and C is 30 years today. How old C will be after 5 years?








  1. View Hint View Answer Discuss in Forum

    Let the present ages of A, B and C be P years, Q years and R years respectively.
    According to question,
    Ten years ago, average age of A and B = 20 years.

    (P - 10) + (Q - 10)
    		= 20
    2

    Correct Option: C

    Let the present ages of A, B and C be P years, Q years and R years respectively.
    According to question,
    Ten years ago, average age of A and B = 20 years.

    (P - 10) + (Q - 10)
    		= 20
    2

    ⇒ P – 10 + Q – 10 =40
    ⇒ P + Q = 60 .....(i)
    Average present age of A, B and C = 30 years
    Again,
    P + Q + R
    		= 30
    3

    ⇒ P + Q + R = 30 × 3 = 90 ....(ii)
    On solving equations (i) and (ii) , we get
    R = 30 years
    Hence, the age of C after 5 years = 30 + 5 = 35 years

  1. A father is 3 times as old his son. 8 years ago, the father was 5 times as old as his son. What is the present age of the son?








  1. View Hint View Answer Discuss in Forum

    Suppose the present age of the son is P years.
    Therefore, the present age of father will be 3P years.
    According to question , Eight years ago, 5 × ( the present age of the son - 8 years ) = ( the present age of father - 8 years )
    5(P – 8) = 3P – 8
    ⇒ 5P – 40 = 3P – 8
    ⇒ 5P – 3P = 40 – 8
    ⇒ 2P = 32

    Correct Option: C

    Suppose the present age of the son is P years.
    Therefore, the present age of father will be 3P years.
    According to question , Eight years ago, 5 × ( the present age of the son - 8 years ) = ( the present age of father - 8 years )
    5(P – 8) = 3P – 8
    ⇒ 5P – 40 = 3P – 8
    ⇒ 5P – 3P = 40 – 8
    ⇒ 2P = 32

    ∴ P =
    32
    		= 16 years
    2

    Therefore , the present age of the son is 16 years.