Problem Based on ages


  1. Ten years ago, the age of Divya was half of the age of Namrata. If the ratio of present ages of both is 3 : 4, the sum of their present ages is:









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    Let the present age of Divya and Namrata are 3x and 4x years respectively;

    Correct Option: A

    Let the present age of Divya and Namrata are 3x and 4x years respectively; then
    According to question,
    Ten years ago, Age of Divya = 3x - 10
    Ten years ago, Age of Namrata = 4x - 10
    Now According to question,
    Ten years ago, the age of Divya was half of the age of Namrata
    3x - 10 = (4x - 10)/2
    ⇒ 6x - 20 = 4x - 10
    ⇒ 2x =10
    ∴ x = 5
    Hence, sum of their ages = 3x + 4x = 7x =7 x 5 = 35 years


  1. The present ages of three persons are in the ratio of 4 : 7: 9. Eight years ago, the sum of their ages was 56. What are their present ages in years?









  1. View Hint View Answer Discuss in Forum

    Let the present age of three persons are 4x, 7x and 9x years respectively.

    Correct Option: C

    Let the present age of three persons are 4x, 7x and 9x years respectively.
    Eight years ago, Ages of three person were 4x - 8, 7x - 8, 9x - 8 years.
    According to question,
    4x - 8 + 7x - 8 + 9x - 8 = 56
    ⇒ 20x - 24 = 54
    ⇒ 20x = 80
    ∴ x = 4
    Hence, their present ages are
    4 x 4 = 16 years,
    7 x 4 = 28 years,
    9 x 4 = 36 years respectively .



  1. The ratio between the present ages of A and B is 5 : 3 respectively. The ratio between A's age 4 years ago and B's age 4 years hence is 1 : 1. The ratio between A's age 4 years hence and B's age 4 year ago is:









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    Let the present ages of A and B are 5x and 3x years respectively.

    Correct Option: B

    Let the present ages of A and B are 5x and 3x years respectively. Then
    A's age 4 years ago = 5x - 4
    B's age 4 years hence = 3x + 4
    According to question,
    The ratio between A's age 4 years ago and B's age 4 years hence is 1 : 1
    (5x - 4)/(3x + 4) = 1 : 1 = 1
    ⇒ 5x - 4 = 3x + 4
    ⇒ 2x = 8
    ∴ x = 4
    present ages of A and B are 20 and 12 years.
    The ratio between A's age 4 years hence and B's age 4 year ago is:
    Hence, required ratio = (20 + 4) : (12 - 4) = 24 : 8 = 3: 1


  1. The ratio of ages of a man and his wife is 4 : 3. After 4 years, this ratio will be 9 : 7 If at the time of marriage the ratio was 5 : 3, then how many years ago were they married?









  1. View Hint View Answer Discuss in Forum

    Let the present ages of the man and his wife are 4x and 3x years respectively.

    Correct Option: B

    Let the present ages of the man and his wife are 4x and 3x years respectively; then
    After 4 years ages of man and his wife will be 4x + 4 and 3x + 4 years.
    According to question,
    After 4 years, this ratio of their ages will be 9 : 7,
    (4x + 4)/ (3x + 4) = 9/7
    ⇒ (4x + 4)7 = 9(3x + 4)
    ⇒ 28x + 28 = 27x + 36
    ∴ x = 8
    Hence, their present ages are 4 x 8 = 32 years and 3 x 8 = 24 years
    If t years ago they were married, then
    (32 - t) /(24 - t) = 5/3
    ⇒ (32 - t)3 = 5(24 - t)
    ⇒ 96 -3t = 120 - 5t
    ⇒ 2t = 24
    t = 12 years



  1. A is two years older than B, who is twice old as old as C. If the sum of the ages of A, B and C be 27, then the age of B in years is:









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    Let us assume the age of B be P years then age of A will be P + 2 and age of C will be P/2 years.

    Correct Option: A

    Let us assume the age of B be P years then age of A will be P + 2 and age of C will be P/2 years.
    Then according to question,
    P + 2 + P + P/2 = 27
    ⇒ P + P + P/2 = 27 - 2
    ⇒ ( 2P + 2P + P)/2 = 25
    ⇒ 5P = 25 x 2
    &there; P = 50/5 = 10 years
    Age of B will be 10 years.