Direction and Distance
 Namita walks 14 meters towards west, then turns to her right and walks 14 meters and then turns to her left and walks 10 meters. Again turning to her left she walks 14 meters. What is the shortest distance (in meters) between her starting point and the present position?

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Draw a figure as per given question.
Correct Option: B
Namita walks 14 meters towards west from starting point S.
(Assume the starting point is S).
Then she turns to her right and walks 14 meters.
And then turns to her left and walks 10 meters.
Again turning to her left she walks 14 meters.
Required answer: DA + SA = 10 + 14 = 24m
 Amit walked 30 meters towards East, took a right turn and walked 40 meters. Then he took a left turn and walked 30 meters. In which direction is he now from the starting point?

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Draw a figure with the help of given below direction figure.
Correct Option: C
The movements of Amit are as shown in Fig (P to Q, Q to R and R to S).
Clearly, his final position is S which is to the South – East from the starting point P.
 A person starts from a point A and travels 3 km east  wards to B and then turns left and travels thrice that distance to reach C. He again turns left and travels five times the distance he covered between A and B and reaches his destination D. The shortest distance between the starting point and the destination is?

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Draw the figure of movement with the help of given below direction graph.
A person starts from a point A and travels 3 km East  Wards to B Then turns left and travels thrice that distance to reach C.
He again turns left and travels five times the distance he covered between A and B and reaches his destination D.
Correct Option: B
Draw the figure of movement with the help of given below direction graph.
A person starts from a point A and travels 3 km East  Wards to B. Then he turns left and travels 9 km to reach C.
He again turns left and travels 15 km and reaches his destination D.
The movements of the person are as shown in Figure
Clearly, AB = 3 km, BC = 3AB = (3 × 3) km = 9 km, CD = 5AB = (5 × 3) km = 15 km,
Draw AE ? CD.
Then, CE = AB = 3 km
AE = BC = 9 km
DE = (CD – CE) = (15 – 3) km = 12 km.
In triangle AED, AD^{2} = AE^{2} + DE^{2}
or AD^{2} = 9^{2} + 12^{2}
or AD^{2} = 81+ 144
or AD^{2} = 225
or AD^{2} = 15^{2}
AD = 15
Required distance = AD = 15 km
 Going 50 m to the South of her house, Radhika turns left and goes another 20 m. Then, turning to the North, she goes 30 m and then starts walking to her house. In which direction is she walking now?

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Draw a figure with the movement of Radhika with the help of direction figure given below.
Correct Option: A
Let us assume her house is situated at point A.
Draw a figure of movement of Radhika.
 I am facing east. I turn 100° in the clockwise direction and then 145° in the anti clock wise direction. Which direction am I facing now?

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Draw a figure, in which a man standing in East direction.
Correct Option: B
Draw a figure first when man is moving in clockwise direction then for anticlockwise. The man will be finally standing in North East position as explain in below figure.