Dual Nature of Radiation and Matter


Dual Nature of Radiation and Matter

  1. The wavelength of a 1 keV photon is 1.24 × 10–9 m. What is the frequency of 1 MeV photon?









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    Here,

    hc
    = 103 eV and hv = 106 eV
    λ

    Hence,
    v =
    103c
    =
    103 × 3 × 108
    λ1.24 × 10-19

    = 2.4 × 1020 Hz

    Correct Option: B

    Here,

    hc
    = 103 eV and hv = 106 eV
    λ

    Hence,
    v =
    103c
    =
    103 × 3 × 108
    λ1.24 × 10-19

    = 2.4 × 1020 Hz


  1. Photoelectric work function of a metal is 1eV. Light of wavelength λ = 3000 Å falls on it. The photo electrons come out with velocity









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    hv = W +
    1
    mv2
    2

    or
    hc
    = W +
    1
    λmv2

    Here λ = 3000 Å = 3000 × 10–10 m
    ​and W = 1 eV = 1.6 × 10–19 joule
    (6.6 × 10-34)(3 × 108)
    3000 × 10-10

    = (1.6 × 10-19) +
    1
    × (9.1 × 10-31)v2
    2

    Solving we get,
    v ≌ 106 m/s

    Correct Option: D

    hv = W +
    1
    mv2
    2

    or
    hc
    = W +
    1
    λmv2

    Here λ = 3000 Å = 3000 × 10–10 m
    ​and W = 1 eV = 1.6 × 10–19 joule
    (6.6 × 10-34)(3 × 108)
    3000 × 10-10

    = (1.6 × 10-19) +
    1
    × (9.1 × 10-31)v2
    2

    Solving we get,
    v ≌ 106 m/s



  1. Energy levels A, B, C of a certain atom correspond to increasing values of energy i.e., EA < EB < EC. If λ1, λ2, λ3 are the wavelengths of radiation corresponding to the transitions C to B, B to A and C to A respectively, which of the following relation is correct?









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    (E2 - E1) = hv =
    hc
    λ

    hc
    = (EC - EB),
    hc
    = (EB - EA)
    λ1λ2

    and
    hc
    = (EC - EA)
    λ3

    Now,
    (EC - EA) = (EC - EB) + (EB - EA)
    or,
    hc
    =
    hc
    +
    hc
    λ3λ1λ2

    or
    1
    =
    1
    +
    1
    λ3λ1λ2

    1
    =
    λ1 + λ2
    λ3λ1λ2

    or λ3 =
    λ1λ2
    λ1 + λ2

    Correct Option: B

    (E2 - E1) = hv =
    hc
    λ

    hc
    = (EC - EB),
    hc
    = (EB - EA)
    λ1λ2

    and
    hc
    = (EC - EA)
    λ3

    Now,
    (EC - EA) = (EC - EB) + (EB - EA)
    or,
    hc
    =
    hc
    +
    hc
    λ3λ1λ2

    or
    1
    =
    1
    +
    1
    λ3λ1λ2

    1
    =
    λ1 + λ2
    λ3λ1λ2

    or λ3 =
    λ1λ2
    λ1 + λ2


  1. A radio transmitter operates at a frequency 880 kHz and a power of 10 kW. The number of photons emitted per second is









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    No. of photons emitted per sec,

    n =
    Power
    Energy of photon

    =
    P
    =
    10000
    hv6.6 × 10-34 × 880 × 103

    = 1.72 × 1031

    Correct Option: A

    No. of photons emitted per sec,

    n =
    Power
    Energy of photon

    =
    P
    =
    10000
    hv6.6 × 10-34 × 880 × 103

    = 1.72 × 1031



  1. The momentum of a photon of an electromagnetic radiation is 3.3 × 10–29​ kg ms–1. What is the frequency of the associated waves ?
    ​[h = 6.6 × 10–34 Js; c = 3 × 108 ms–1)









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    As λ =
    h
    and λ =
    c
    ;
    Pv

    so v =
    c
    =
    cP
    λh

    3 × 108 × =
    3.3 × 10-29
    6.6 × 10-34

    = 1.5 × 1013 Hz

    Correct Option: A

    As λ =
    h
    and λ =
    c
    ;
    Pv

    so v =
    c
    =
    cP
    λh

    3 × 108 × =
    3.3 × 10-29
    6.6 × 10-34

    = 1.5 × 1013 Hz