Dual Nature of Radiation and Matter
- The wavelength of a 1 keV photon is 1.24 × 10–9 m. What is the frequency of 1 MeV photon?
-
View Hint View Answer Discuss in Forum
Here,
hc = 103 eV and hv = 106 eV λ
Hence,v = 103c = 103 × 3 × 108 λ 1.24 × 10-19
= 2.4 × 1020 HzCorrect Option: B
Here,
hc = 103 eV and hv = 106 eV λ
Hence,v = 103c = 103 × 3 × 108 λ 1.24 × 10-19
= 2.4 × 1020 Hz
- Photoelectric work function of a metal is 1eV. Light of wavelength λ = 3000 Å falls on it. The photo electrons come out with velocity
-
View Hint View Answer Discuss in Forum
hv = W + 1 mv2 2 or hc = W + 1 λ mv2
Here λ = 3000 Å = 3000 × 10–10 m
and W = 1 eV = 1.6 × 10–19 joule∴ (6.6 × 10-34)(3 × 108) 3000 × 10-10 = (1.6 × 10-19) + 1 × (9.1 × 10-31)v2 2
Solving we get,
v ≌ 106 m/sCorrect Option: D
hv = W + 1 mv2 2 or hc = W + 1 λ mv2
Here λ = 3000 Å = 3000 × 10–10 m
and W = 1 eV = 1.6 × 10–19 joule∴ (6.6 × 10-34)(3 × 108) 3000 × 10-10 = (1.6 × 10-19) + 1 × (9.1 × 10-31)v2 2
Solving we get,
v ≌ 106 m/s
- Energy levels A, B, C of a certain atom correspond to increasing values of energy i.e., EA < EB < EC. If λ1, λ2, λ3 are the wavelengths of radiation corresponding to the transitions C to B, B to A and C to A respectively, which of the following relation is correct?
-
View Hint View Answer Discuss in Forum
(E2 - E1) = hv = hc λ ∴ hc = (EC - EB), hc = (EB - EA) λ1 λ2 and hc = (EC - EA) λ3
Now,
(EC - EA) = (EC - EB) + (EB - EA)or, hc = hc + hc λ3 λ1 λ2 or 1 = 1 + 1 λ3 λ1 λ2 ∴ 1 = λ1 + λ2 λ3 λ1λ2 or λ3 = λ1λ2 λ1 + λ2 Correct Option: B
(E2 - E1) = hv = hc λ ∴ hc = (EC - EB), hc = (EB - EA) λ1 λ2 and hc = (EC - EA) λ3
Now,
(EC - EA) = (EC - EB) + (EB - EA)or, hc = hc + hc λ3 λ1 λ2 or 1 = 1 + 1 λ3 λ1 λ2 ∴ 1 = λ1 + λ2 λ3 λ1λ2 or λ3 = λ1λ2 λ1 + λ2
- A radio transmitter operates at a frequency 880 kHz and a power of 10 kW. The number of photons emitted per second is
-
View Hint View Answer Discuss in Forum
No. of photons emitted per sec,
n = Power Energy of photon = P = 10000 hv 6.6 × 10-34 × 880 × 103
= 1.72 × 1031Correct Option: A
No. of photons emitted per sec,
n = Power Energy of photon = P = 10000 hv 6.6 × 10-34 × 880 × 103
= 1.72 × 1031
- The momentum of a photon of an electromagnetic radiation is 3.3 × 10–29 kg ms–1. What is the frequency of the associated waves ?
[h = 6.6 × 10–34 Js; c = 3 × 108 ms–1)
-
View Hint View Answer Discuss in Forum
As λ = h and λ = c ; P v so v = c = cP λ h 3 × 108 × = 3.3 × 10-29 6.6 × 10-34
= 1.5 × 1013 HzCorrect Option: A
As λ = h and λ = c ; P v so v = c = cP λ h 3 × 108 × = 3.3 × 10-29 6.6 × 10-34
= 1.5 × 1013 Hz