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Dual Nature of Radiation and Matter

  1. Photoelectric work function of a metal is 1eV. Light of wavelength λ = 3000 Å falls on it. The photo electrons come out with velocity
    1. 10 metres/sec ​
    2. 102 metres/sec ​
    3. 104 metres/sec
    4. 106 metres/sec
Correct Option: D

hv = W +
1
mv2
2

or
hc
= W +
1
λmv2

Here λ = 3000 Å = 3000 × 10–10 m
​and W = 1 eV = 1.6 × 10–19 joule
(6.6 × 10-34)(3 × 108)
3000 × 10-10

= (1.6 × 10-19) +
1
× (9.1 × 10-31)v2
2

Solving we get,
v ≌ 106 m/s



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