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Photoelectric work function of a metal is 1eV. Light of wavelength λ = 3000 Å falls on it. The photo electrons come out with velocity
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- 10 metres/sec
- 102 metres/sec
- 104 metres/sec
- 106 metres/sec
Correct Option: D
hv = W + | mv2 | 2 |
or | = W + | |||
λ | mv2 |
Here λ = 3000 Å = 3000 × 10–10 m
and W = 1 eV = 1.6 × 10–19 joule
∴ | 3000 × 10-10 |
= (1.6 × 10-19) + | × (9.1 × 10-31)v2 | 2 |
Solving we get,
v ≌ 106 m/s