Games And Tournament
Direction: Kolkata Premier League has 16 players seeded from 1 to 16. These players are divided in 4 groups namely South Kolkata, North Kolkata, Central Kolkata and Saltlake. 16 players are divided in these groups as follows :-
South Kolkata : 1, 8, 9, 16
North Kolkata : 2, 7, 10, 15
Central Kolkata : 3, 6, 11, 14
Saltlake : 4, 5, 12,13
In stage I :, each player in a group plays with all the other members in their group exactly once. 2 from each group is selected for stage II based on their number of points. A player qualifying for stage II carries forward only those points that he gained stage I against the another player who qualifies for stage II.
In stage II :, total 8 players (2 from each group) advanced to stage II, where each player plays every other player except the player from same group. At the end of stage II, the top 4 players on the basis of points would qualify for the IIIrd stage the Semi-Final stage.
Stage III : (Semi-Final), winners of the Semi-Final advanced to the final round and losers play for 3rd place. The following more rules of tournament is as follows :
(i) Points in stage I and stage II are awarded as follows : winner 2 points, looser 0 points.
(ii) An ‘upset’ is caused when, in any match a lower seeded player beats a higher seeded player.
(iii) There is no ties at any stage.
(iv) If points of the two players at the end of any stage are same then there is a complex rule to calculate the tie breaker.
(v) Seed 1 is the highest seed and seed 16 is the lowest rank seed.
- If there is no upset in stage 1 then the lowest seeded player who can win the tournament is -
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In stage I, in a group in total 6 matches and that will have 12 points in total.
Total number of matches in this stage is 4 × 6 = 24
In stage II, total 8 players and they play each other except a player who comes from same group but point of their match in stage I is carried forward hence in stage II total points is 28 × 2 = 56.
Number of matches in stage II is 7 × ( 8/2 ) – 4 = 24Correct Option: B
In stage I, in a group in total 6 matches and that will have 12 points in total.
Total number of matches in this stage is 4 × 6 = 24
In stage II, total 8 players and they play each other except a player who comes from same group but point of their match in stage I is carried forward hence in stage II total points is 28 × 2 = 56.
Number of matches in stage II is 7 × ( 8/2 ) – 4 = 24
In stage 1 a player has to win minimum 1 match to advance to the next stage.
Now consider the different groups,
South Kolkata : 1, 8, 9, 16 [seed 9 can advance after beating seed 16 without an upset]
North Kolkata : 2, 7, 10, 15 [seed 10 can advance after beating seed 15 without an upset]
Central Kolkata : 3, 6, 11, 14 [seed 11 can advance after beating seed 14 without an upset]
Saltlake : 4, 5, 12,13 [seed 12 can advance after beating seed 113 without an upset] So seed 12 is the lowest seed who can advance to stage II without causing Upset in stage I, and can win the tournament [Please note here that in stage II or semifinal there may be an Upset
- What is the total number of points ( From all the stages including final) in the tournament?
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View Hint View Answer Discuss in Forum
In stage I, in a group in total 6 matches and that will have 12 points in total.
Total number of matches in this stage is 4 × 6 = 24
In stage II, total 8 players and they play each other except a player who comes from same group but point of their match in stage I is carried forward hence in stage II total points is 28 × 2 = 56.
Number of matches in stage II is 7 × ( 8/2 ) – 4 = 24Correct Option: C
In stage I, in a group in total 6 matches and that will have 12 points in total.
Total number of matches in this stage is 4 × 6 = 24
In stage II, total 8 players and they play each other except a player who comes from same group but point of their match in stage I is carried forward hence in stage II total points is 28 × 2 = 56.
Number of matches in stage II is 7 × ( 8/2 ) – 4 = 24
Total number of matches are as follows
Stage I: 24
Stage II: 24
Semifinal: 2
For 3rd place (Looser of semi final): 1
Final: 1
Total number of matches is 52 and hence total number of points is 52 × 2 = 104
- Find the ratio of number of matches at Stage I and Stage II.
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View Hint View Answer Discuss in Forum
In stage I, in a group in total 6 matches and that will have 12 points in total.
Total number of matches in this stage is 4 × 6 = 24
In stage II, total 8 players and they play each other except a player who comes from same group but point of their match in stage I is carried forward hence in stage II total points is 28 × 2 = 56.
Number of matches in stage II is 7 × ( 8/2 ) – 4 = 24Correct Option: D
In stage I, in a group in total 6 matches and that will have 12 points in total.
Total number of matches in this stage is 4 × 6 = 24
In stage II, total 8 players and they play each other except a player who comes from same group but point of their match in stage I is carried forward hence in stage II total points is 28 × 2 = 56.
Number of matches in stage II is 7 × ( 8/2 ) – 4 = 24
Total number of matches are as follows:
Stage I : 24
Stage II : 24
And required ratio is 1 : 1.
Direction: 7 players Ahaskar, Bhanu, Chandan, Dripto, Eshan, Faisal and Gaurav participate in a Carrom tournament in which each player plays exactly once against each of the other 6 players. The tournament was held on 3 stages such that an equal number of matches is played on all the 3 stages. As per the rules of the tournament winner will get 2 points and looser will get 0 point while none of the matches ends in a draw. Points scored by all the players is distinct.
Further known about the tournament is:
Stage 1
- Gaurav loses to Bhanu but wins against Ahaskar and Chandan.
- Dripto wins against Chandan and Eshan.
- Faisal loses to Ahaskar and Bhanu.
Stage 2
- Faisal loses to Chandan, Dripto, Eshan and Gaurav.
- Only one player, wins more than one match in stage 2.
- Chandan won at most 1 match in this stage
Stage 3
- Bhanu wins against Chandan, Dripto and Eshan.
- Eshan loses to Ahaskar and Chandan.
- Gaurav wins exactly two matches in this stage.
- If result of stage 2 is interchanged i.e winner becomes looser and vice versa and as a result 3 players got same points then Dripto got how many points?
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Total number of matches is 21 when divided in 3 stages we will get 7 matches in one stage.
We can find the result on the basis of table .Correct Option: A
Total number of matches is 21 when divided in 3 stages we will get 7 matches in one stage.
From the given table Ahaskar, Faisal and Gaurav won 4 matches then Dripto won only 2 matches.
- If result of stage 2 is interchanged i.e winner becomes looser and vice versa then who won the maximum points in the tournament?
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View Hint View Answer Discuss in Forum
Total number of matches is 21 when divided in 3 stages we will get 7 matches in one stage.
We can find the result on the basis of table .Correct Option: B
Total number of matches is 21 when divided in 3 stages we will get 7 matches in one stage.Hence , required answer is Bhanu.
The new result will be as follows :
