Numerical Ability
 A wire would enclose an area of 1936 m2, if it is bent into a square. The wire is cut into two pieces. The longer piece is thrice as long as the shorter piece. The long and the short pieces are bent into a square and a circle, respectively. Which of the following choices is closest to the sum of the areas enclosed by the two pieces in square meters?

 1096
 1111
 1243
 2486

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Side of the square = 44 m
Long piece = 44 × 3 = 132 m and short piece = 44 m
Hence, equating these values with the perimeter of square and circle respectively we will get the required answer as 1243 m2.Correct Option: C
Side of the square = 44 m
Long piece = 44 × 3 = 132 m and short piece = 44 m
Hence, equating these values with the perimeter of square and circle respectively we will get the required answer as 1243 m2.
 Forty students watched films, A, B and C over a week. Each student watched either only one film or all three. Thirteen students watched film A, sixteen students watched film B and nineteen students watched film C. How many students watched all three films?

 0
 2
 4
 8

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13 + 16 + 19 = 48 > 40
Hence, 4 students would have watched all three due to which there is a double counting of 4 × 2 = 8.Correct Option: C
13 + 16 + 19 = 48 > 40
Hence, 4 students would have watched all three due to which there is a double counting of 4 × 2 = 8.
 A contract is to be completed in 52 days and 125 identical robots were employed, each operational for 7 hours a day. After 39 days, fiveseventh of the work was completed. How many additional robots would be required to complete the work on time, if each robot is now operational for 8 hours a day?

 50
 89
 146
 175

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125 × 7 × 39 = 5x/7
∴ x or total work = 25 × 39 × 49
Hence, [125 + y(additional robot)] × 8 × 13 = 25 × 39 × 49 × 2/7
Thus, the given data is insufficient to answer the question.Correct Option: D
125 × 7 × 39 = 5x/7
∴ x or total work = 25 × 39 × 49
Hence, [125 + y(additional robot)] × 8 × 13 = 25 × 39 × 49 × 2/7
Thus, the given data is insufficient to answer the question.
 An unbiased coin is tossed six times in a row and four different such trials are conducted. One trial implies six tosses of the coin. If H stands for head and T stands for tail, the foilowing are the observations from the four trials:
(1) HTHTHT
(2) TTHHHT
(3) HTTHHT
(4) HHHT ________.
Which statement describing the last two coin tosses of the fourth trial has the highest probability of being correct?

 Two T will occur
 One H and one T will occur
 Two H will occur
 One H will be followed by one T

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NA
Correct Option: B
NA
 The value of the expression
1 + 1 + 1 is  1 + log_{u}VW 1 + log_{v}WU 1 + log_{w}UV

  1
 0
 1
 3

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NA
Correct Option: C
NA