Numerical Ability


  1. A wire would enclose an area of 1936 m2, if it is bent into a square. The wire is cut into two pieces. The longer piece is thrice as long as the shorter piece. The long and the short pieces are bent into a square and a circle, respectively. Which of the following choices is closest to the sum of the areas enclosed by the two pieces in square meters?
    1. 1096
    2. 1111
    3. 1243
    4. 2486

  1. View Hint View Answer Discuss in Forum

    Side of the square = 44 m
    Long piece = 44 × 3 = 132 m and short piece = 44 m
    Hence, equating these values with the perimeter of square and circle respectively we will get the required answer as 1243 m2.

    Correct Option: C

    Side of the square = 44 m
    Long piece = 44 × 3 = 132 m and short piece = 44 m
    Hence, equating these values with the perimeter of square and circle respectively we will get the required answer as 1243 m2.


  1. Forty students watched films, A, B and C over a week. Each student watched either only one film or all three. Thirteen students watched film A, sixteen students watched film B and nineteen students watched film C. How many students watched all three films?
    1. 0
    2. 2
    3. 4
    4. 8

  1. View Hint View Answer Discuss in Forum

    13 + 16 + 19 = 48 > 40
    Hence, 4 students would have watched all three due to which there is a double counting of 4 × 2 = 8.

    Correct Option: C

    13 + 16 + 19 = 48 > 40
    Hence, 4 students would have watched all three due to which there is a double counting of 4 × 2 = 8.



  1. A contract is to be completed in 52 days and 125 identical robots were employed, each operational for 7 hours a day. After 39 days, five-seventh of the work was completed. How many additional robots would be required to complete the work on time, if each robot is now operational for 8 hours a day?
    1. 50
    2. 89
    3. 146
    4. 175

  1. View Hint View Answer Discuss in Forum

    125 × 7 × 39 = 5x/7
    ∴ x or total work = 25 × 39 × 49
    Hence, [125 + y(additional robot)] × 8 × 13 = 25 × 39 × 49 × 2/7
    Thus, the given data is insufficient to answer the question.

    Correct Option: D

    125 × 7 × 39 = 5x/7
    ∴ x or total work = 25 × 39 × 49
    Hence, [125 + y(additional robot)] × 8 × 13 = 25 × 39 × 49 × 2/7
    Thus, the given data is insufficient to answer the question.


  1. An unbiased coin is tossed six times in a row and four different such trials are conducted. One trial implies six tosses of the coin. If H stands for head and T stands for tail, the foilowing are the observations from the four trials:
    (1) HTHTHT
    (2) TTHHHT
    (3) HTTHHT
    (4) HHHT ________.
    Which statement describing the last two coin tosses of the fourth trial has the highest probability of being correct?
    1. Two T will occur
    2. One H and one T will occur
    3. Two H will occur
    4. One H will be followed by one T

  1. View Hint View Answer Discuss in Forum

    NA

    Correct Option: B

    NA



  1. The value of the expression
    1
    +
    1
    +
    1
    is -
    1 + loguVW1 + logvWU1 + logwUV
    1. - 1
    2. 0
    3. 1
    4. 3

  1. View Hint View Answer Discuss in Forum

    NA

    Correct Option: C

    NA