Numerical Ability
 The value of the expression
1 + 1 + 1 is  1 + log_{u}VW 1 + log_{v}WU 1 + log_{w}UV

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NA
Correct Option: C
NA
 An unbiased coin is tossed six times in a row and four different such trials are conducted. One trial implies six tosses of the coin. If H stands for head and T stands for tail, the foilowing are the observations from the four trials:
(1) HTHTHT
(2) TTHHHT
(3) HTTHHT
(4) HHHT ________.
Which statement describing the last two coin tosses of the fourth trial has the highest probability of being correct?

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NA
Correct Option: B
NA
 A contract is to be completed in 52 days and 125 identical robots were employed, each operational for 7 hours a day. After 39 days, fiveseventh of the work was completed. How many additional robots would be required to complete the work on time, if each robot is now operational for 8 hours a day?

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125 × 7 × 39 = 5x/7
∴ x or total work = 25 × 39 × 49
Hence, [125 + y(additional robot)] × 8 × 13 = 25 × 39 × 49 × 2/7
Thus, the given data is insufficient to answer the question.Correct Option: D
125 × 7 × 39 = 5x/7
∴ x or total work = 25 × 39 × 49
Hence, [125 + y(additional robot)] × 8 × 13 = 25 × 39 × 49 × 2/7
Thus, the given data is insufficient to answer the question.
 A rectangle becomes a square when its length and breadth are reduced by 10 m and 5 m, respectively. during this process, the rectangle loses 650 m² of area. What is the area of the original rectangle in square meters?

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Let the initial length of rectangle is l and breath is b. Now if length is reduced by 10 m and breath is reduced by 5 m then it becomes square.
∴ l – 10 = b – 5
[∵ In square length = breadth]
∴ l – b = 5
Given, initial, Area (A) = l × b
Now according to question,
(l – 10) (b – 5) = A – 650
∴ lb – 10b – 5l + 50 = A – 650
∴ A – 10b – 5l = A – 700
∴ 10b + 5l = 700
∴ 10b + 5 (b + 5) = 700
∴ 15b + 25 = 700
∴ 15b = 700 – 25
∴ 15b = 675
⇒ b = 45 m
∴ l = 45 + 5 = 50 m
∴ Area of original rectangle (A) = (45 × 50)m² = 2250 m².Correct Option: B
Let the initial length of rectangle is l and breath is b. Now if length is reduced by 10 m and breath is reduced by 5 m then it becomes square.
∴ l – 10 = b – 5
[∵ In square length = breadth]
∴ l – b = 5
Given, initial, Area (A) = l × b
Now according to question,
(l – 10) (b – 5) = A – 650
∴ lb – 10b – 5l + 50 = A – 650
∴ A – 10b – 5l = A – 700
∴ 10b + 5l = 700
∴ 10b + 5 (b + 5) = 700
∴ 15b + 25 = 700
∴ 15b = 700 – 25
∴ 15b = 675
⇒ b = 45 m
∴ l = 45 + 5 = 50 m
∴ Area of original rectangle (A) = (45 × 50)m² = 2250 m².
 A wire would enclose an area of 1936 m2, if it is bent into a square. The wire is cut into two pieces. The longer piece is thrice as long as the shorter piece. The long and the short pieces are bent into a square and a circle, respectively. Which of the following choices is closest to the sum of the areas enclosed by the two pieces in square meters?

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Side of the square = 44 m
Long piece = 44 × 3 = 132 m and short piece = 44 m
Hence, equating these values with the perimeter of square and circle respectively we will get the required answer as 1243 m2.Correct Option: C
Side of the square = 44 m
Long piece = 44 × 3 = 132 m and short piece = 44 m
Hence, equating these values with the perimeter of square and circle respectively we will get the required answer as 1243 m2.