Network theory miscellaneous
- Two AC sources feed a common variable resistive load as shown in figure. Under the maximum power transfer condition, the power absorbed by the load resistance RL is—
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The given circuit:
Zth = (6 + j8) || (6 + j8)
= (6 + j8)/2 = (3 + j4) Ω
Equivalent circuit for Vth:
Applying KCLVth – 110 0° + Vth – 90 0° = 0 6 + j8 6 + j8
orVth = 200 0° = 100 0° 2
Now, for maximum power transfer theorem,
ZL = Z*th
or
Rth = RL
and power absorbed by RLPmax = V2th 4RL
orPmax = (100)2 4 × 5
or
Pmax = 500W
where RL = R2s + X2s
or
RL = 32 + 42 (since RL = 3 + j4)
or
RL = 5Ω
Hence alternative (C) is the correct choice.Correct Option: C
The given circuit:
Zth = (6 + j8) || (6 + j8)
= (6 + j8)/2 = (3 + j4) Ω
Equivalent circuit for Vth:
Applying KCLVth – 110 0° + Vth – 90 0° = 0 6 + j8 6 + j8
orVth = 200 0° = 100 0° 2
Now, for maximum power transfer theorem,
ZL = Z*th
or
Rth = RL
and power absorbed by RLPmax = V2th 4RL
orPmax = (100)2 4 × 5
or
Pmax = 500W
where RL = R2s + X2s
or
RL = 32 + 42 (since RL = 3 + j4)
or
RL = 5Ω
Hence alternative (C) is the correct choice.