Network theory miscellaneous


  1. Two AC sources feed a common variable resistive load as shown in figure. Under the maximum power transfer condition, the power absorbed by the load resistance RL is—











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    The given circuit:

    Zth = (6 + j8) || (6 + j8)
    = (6 + j8)/2 = (3 + j4) Ω
    Equivalent circuit for Vth:

    Applying KCL

    Vth – 110   0°
    +
    Vth – 90   0°
    = 0
    6 + j86 + j8

    or
    Vth =
    200   0°
    = 100   0°
    2

    Now, for maximum power transfer theorem,
    ZL = Z*th
    or
    Rth = RL
    and power absorbed by RL
    Pmax =
    V2th
    4RL

    or
    Pmax =
    (100)2
    4 × 5

    or
    Pmax = 500W
    where RL = R2s + X2s
    or
    RL = 32 + 42 (since RL = 3 + j4)
    or
    RL = 5Ω
    Hence alternative (C) is the correct choice.

    Correct Option: C

    The given circuit:

    Zth = (6 + j8) || (6 + j8)
    = (6 + j8)/2 = (3 + j4) Ω
    Equivalent circuit for Vth:

    Applying KCL

    Vth – 110   0°
    +
    Vth – 90   0°
    = 0
    6 + j86 + j8

    or
    Vth =
    200   0°
    = 100   0°
    2

    Now, for maximum power transfer theorem,
    ZL = Z*th
    or
    Rth = RL
    and power absorbed by RL
    Pmax =
    V2th
    4RL

    or
    Pmax =
    (100)2
    4 × 5

    or
    Pmax = 500W
    where RL = R2s + X2s
    or
    RL = 32 + 42 (since RL = 3 + j4)
    or
    RL = 5Ω
    Hence alternative (C) is the correct choice.