Two AC sources feed a common variable resistive load as

Two AC sources feed a common variable resistive load as shown in figure. Under the maximum power transfer condition, the power absorbed by the load resistance R_L is—

The given circuit:

Z_th = (6 + j8) || (6 + j8)
= (6 + j8)/2 = (3 + j4) Ω
Equivalent circuit for V_th:

Applying KCL

V_th – 110 0°	+	V_th – 90 0°	= 0
6 + j8		6 + j8

V_th =	200 0°	= 100 0°
	2

Now, for maximum power transfer theorem,
Z_L = Z^*_th
or
R_th = R_L
and power absorbed by R_L

P_max =	V²_th
	4R_L

P_max =	(100)²
	4 × 5

or
P_max = 500W
where R_L = R²_s + X₂_s
or
R_L = 3² + 4² (since R_L = 3 + j4)
or
R_L = 5Ω
Hence alternative (C) is the correct choice.