-
In the AC network shown in the figure, the phasor voltage VAB (in Volts) is—
-
- 0
- 5 ∠ 30°
- 12·5 ∠ 30°
- 17 ∠ 30°
- 0
Correct Option: D
The given network:
img src="http://images.interviewmania.com/wp-content/uploads/2019/05/Ans120.png">
Applying KCL at node A:
| + | = 5 30° | ||
| 5 – j3 | 5 + j3 |
or
| = 5 30° | |
| (5 + j3) (5 – j3) |
or
| VA | = 5 30° | |
| 25 + 9 |
or
VA = 17 30°
Hence alternative (D) is the correct choice.
