Correct Option: D

The given circuit:

From figure

V – 20    0°	+	V	= 0·5Vx ......…(i)
10		20

and V – 20 0° = – V_x
or
V_x = 20 0° – V …(ii)

Now,	V – 20    0°	+	V	= 0·5 [20 0° – V]
	10		20

or

V	1	+	1	+	1	= 2    0° + 10    0°
	10		20		2

or
V = 18·46 0°
and
V_x = 20 0° – V = 20 0° – 18·46 0°
= 1·54 0°
Hence power delivered by the dependent source

=	V × 0·5Vx	i.e.	Vm Im	cos θ
	2		2

=	18·46 × 0·5 × 1·54
	2

= 7·107W
Hence alternative (D) is the correct choice.