Physical World, Units and Measurements
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The dimensions of a, b and c are respectivelyThe velocity v of a particle at time t is given by v = at + b , where a, b and c are constant. t + c
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Dimension of a. t = dimension of velocity
a .t = L T-1 ⇒ a = LT-2
Dimension of c = dimension of t
(two physical quantity of same dimension can only be added)
So, dimension of c = TDimension of b = Dimension of v t + c b = L T-1 ⇒ b.T-1 = LT-1 ⇒ b = L T + T
So, answer is LT-2, L & T
Correct Option: D
Dimension of a. t = dimension of velocity
a .t = L T-1 ⇒ a = LT-2
Dimension of c = dimension of t
(two physical quantity of same dimension can only be added)
So, dimension of c = TDimension of b = Dimension of v t + c b = L T-1 ⇒ b.T-1 = LT-1 ⇒ b = L T + T
So, answer is LT-2, L & T
- The ratio of the dimension of Planck’s constant and that of the moment of inertia is the dimension of
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Plank 's constant = 2πIω Moment of inertia n I [ As nh = Iω ] 2π 2πI(2πf) = 4π2 f = [T-1] nI n Correct Option: B
Plank 's constant = 2πIω Moment of inertia n I [ As nh = Iω ] 2π 2πI(2πf) = 4π2 f = [T-1] nI n
- The dimensions of universal gravitational constant are
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F = G M1m1 ⇒ G = F r2 r2 M1m1 ∴ dimension of G is MLT-2 [L2] = M-1L3T-2 [M] [M] Correct Option: B
F = G M1m1 ⇒ G = F r2 r2 M1m1 ∴ dimension of G is MLT-2 [L2] = M-1L3T-2 [M] [M]
- The dimensions of Planck’s constant are same as
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We know that E = hυ
h = E = [ML2T-2] = [ML2T-1] υ [T-1]
Angular momentum = Iω
= [ML2][T – 1] = [ML2T – 1]Correct Option: D
We know that E = hυ
h = E = [ML2T-2] = [ML2T-1] υ [T-1]
Angular momentum = Iω
= [ML2][T – 1] = [ML2T – 1]
- Which one of the following groups have quantities that do not have the same dimensions?
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Force has dimension [MLT – 2] while impulse has dimension [MLT – 1], both have different dimensions.
Correct Option: C
Force has dimension [MLT – 2] while impulse has dimension [MLT – 1], both have different dimensions.