Physical World, Units and Measurements
- The dimensions of ( μ0 ∊0 ) – 1 / 2 are
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(μ0ε0)-1 / 2 = 1 = c : speed of light √μ0ε0
where ε0 = permittivity of free space
μ0 = permeability of free space
So dimensions are [LT – 1]Correct Option: C
(μ0ε0)-1 / 2 = 1 = c : speed of light √μ0ε0
where ε0 = permittivity of free space
μ0 = permeability of free space
So dimensions are [LT – 1]
- The unit of permittivity of free space, εo is
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ε0 = q2 (r2) 4 π F
⇒ unit of εo is (coulomb)2 / newton-metre2Correct Option: D
ε0 = q2 (r2) 4 π F
⇒ unit of εo is (coulomb)2 / newton-metre2
- In a particular system, the unit of length, mass and time are chosen to be 10 cm, 10 g and 0.1 s respectively. The unit of force in this system will be equivalent to
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[F] = MLT – 2 = (10g) (10 cm) (0.1s) – 2
= (10 – 2 kg) (10 – 1m) (10 – 1s) – 2 = 10 – 1 N.Correct Option: A
[F] = MLT – 2 = (10g) (10 cm) (0.1s) – 2
= (10 – 2 kg) (10 – 1m) (10 – 1s) – 2 = 10 – 1 N.
- The unit of the Stefan-Boltzmann's constant is
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E = σAT4
E is energy dissipated per second.σ = E = Watt AT4 m2 K4 Correct Option: A
E = σAT4
E is energy dissipated per second.σ = E = Watt AT4 m2 K4
- If x = at + bt2, where x is the distance travelled by the body in kilometers while t is the time in seconds, then the unit of b is
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[x] = [bt2].
Hence [b] = [x / t2] = km/s2.Correct Option: C
[x] = [bt2].
Hence [b] = [x / t2] = km/s2.