Physical World, Units and Measurements


  1. P represents radiation pressure, c represents speed of light and S represents radiation energy striking unit area per sec. The non zero integers x, y, z such that Px Sy cz is dimensionless are​​









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    Try out the given alternatives. ​
    When x = 1, y =  – 1, z = 1 ​

    Px Sy cz = P1 S-1 c1 =
    Pc
    S

    =
    [M L – 1 T-2 [LT – 1]
    = M0L0T0
    [M L 2 T– 2 / L2 T]

    Correct Option: C

    Try out the given alternatives. ​
    When x = 1, y =  – 1, z = 1 ​

    Px Sy cz = P1 S-1 c1 =
    Pc
    S

    =
    [M L – 1 T-2 [LT – 1]
    = M0L0T0
    [M L 2 T– 2 / L2 T]


  1. Turpentine oil is flowing through a tube of length L and radius r. ​The pressure difference between the two ends of the tube is p. The viscosity of oil is given by
    η =
    p(r2 - x2)
    4vl

    where v is the velocity of oil at a distance x from the axis of the tube. The dimensions of η are ​









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    h =
    p(r2 - x2)
    =
    [ML – 1T-2] [L2]
    = [ML – 1T – 1]
    4vl[LT – 1] [L]

    Correct Option: D

    h =
    p(r2 - x2)
    =
    [ML – 1T-2] [L2]
    = [ML – 1T – 1]
    4vl[LT – 1] [L]



  1. The time dependence of a physical quantity p is given by p = p0 exp ( – α t2), where α is a constant and t is the time. The constant α  ​









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    In p = p0 exp ( – αt2), αt2 dimensionless

    ∴ α -
    I
    -
    I
    - [T-2]
    t2T2

    Correct Option: B

    In p = p0 exp ( – αt2), αt2 dimensionless

    ∴ α -
    I
    -
    I
    - [T-2]
    t2T2


  1. Which of the following is a dimensional constant?









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    A quantity which has dimensions and a constant value is called dimensional constant. Therefore, gravitational gravitational constant (G) is a dimensional constant.

    Correct Option: D

    A quantity which has dimensions and a constant value is called dimensional constant. Therefore, gravitational gravitational constant (G) is a dimensional constant.



  1. Which of the following will have the dimensions of time​​​









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    e = - L
    di
    .........(1)
    dt

    e = iR​​.........(2)
    From (1) & (2) , iR = - L
    di
    dt

    ∴​ Dimension of L.H.S. = Dimension of R.H.S. ​
    [A] R = L [AT – 1] ⇒
    L
    = [T]
    R

    Correct Option: C

    e = - L
    di
    .........(1)
    dt

    e = iR​​.........(2)
    From (1) & (2) , iR = - L
    di
    dt

    ∴​ Dimension of L.H.S. = Dimension of R.H.S. ​
    [A] R = L [AT – 1] ⇒
    L
    = [T]
    R