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The dimensions of a, b and c are respectivelyThe velocity v of a particle at time t is given by v = at + b , where a, b and c are constant. t + c
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- L2, T and LT2
- LT2, LT and L
- L, LT and T2
- LT– 2, L and T
Correct Option: D
Dimension of a. t = dimension of velocity
a .t = L T-1 ⇒ a = LT-2
Dimension of c = dimension of t
(two physical quantity of same dimension can only be added)
So, dimension of c = T
Dimension of | = Dimension of v | |
t + c |
= L T-1 ⇒ b.T-1 = LT-1 ⇒ b = L | ||
T + T |
So, answer is LT-2, L & T