Motion in a Plane


  1. Two bodies of same mass are projected with the same velocity at an angle 30° and 60° respectively. The ratio of their horizontal ranges will be​​​









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    Horizontal range is same when angle of projection is θ or (90° – θ).

    Correct Option: A

    Horizontal range is same when angle of projection is θ or (90° – θ).


  1. The maximum range of a gun of horizontal terrain is 16 km. If g = 10 ms–2, then muzzle velocity of a shell must be​​​









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    Rmax =
    v2
    = 16000 [ 6 km = 16000 m ]
    g

    or v = (16000 g)1 / 2 = (16000 × 10)1 / 2
    = 400 ms –1

    Correct Option: C

    Rmax =
    v2
    = 16000 [ 6 km = 16000 m ]
    g

    or v = (16000 g)1 / 2 = (16000 × 10)1 / 2
    = 400 ms –1



  1. If a body  A  of mass  M  is thrown with velocity v  at an angle of 30° to the horizontal and another body  B  of the  same mass is thrown with the same speed at an angle of 60° to the horizontal, the ratio of horizontal range of A to B will be









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    Horizontal range is same when angle of projection with the horizonatal is θ and (90° – θ).

    Correct Option: B

    Horizontal range is same when angle of projection with the horizonatal is θ and (90° – θ).


  1. Two projectiles are fired from the same point with the same speed at angles of projection 60° and 30° respectively. Which one of the following is true?​​​









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    Given, u1 = u2 = u, θ1 = 60° , θ2 = 30° ​
    In 1st case, we know that range

    R1 =
    u2 sin 2(60°)
    =
    u2 sin 120°
    gg

    =
    u2 sin(90° + 30°)
    g

    =
    u2 (cos 30°)
    =
    3 u2
    g2g

    In 2nd case, when θ2 = 30° , then
    R2 =
    u2 sin 60°
    =
    3 u2
    ⇒ R1 = R2
    g2g

    [we get same value of ranges].

    Correct Option: B

    Given, u1 = u2 = u, θ1 = 60° , θ2 = 30° ​
    In 1st case, we know that range

    R1 =
    u2 sin 2(60°)
    =
    u2 sin 120°
    gg

    =
    u2 sin(90° + 30°)
    g

    =
    u2 (cos 30°)
    =
    3 u2
    g2g

    In 2nd case, when θ2 = 30° , then
    R2 =
    u2 sin 60°
    =
    3 u2
    ⇒ R1 = R2
    g2g

    [we get same value of ranges].



  1. For angles of projection of a projectile (45° – θ) and (45° + θ), the horizontal ranges described by the projectile are in the ratio of​









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    ​(45° – θ) & (45° + θ) are complementary angles as 45° – θ + 45° + θ = 90° . We know that if angle of projection of two projectiles make complementary angles, their ranges are equal. In this case also, the range will be same. So the ratio is 1 : 1.

    Correct Option: D

    ​(45° – θ) & (45° + θ) are complementary angles as 45° – θ + 45° + θ = 90° . We know that if angle of projection of two projectiles make complementary angles, their ranges are equal. In this case also, the range will be same. So the ratio is 1 : 1.