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For angles of projection of a projectile (45° – θ) and (45° + θ), the horizontal ranges described by the projectile are in the ratio of
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- 1 : 3
- 1 : 2
- 2 : 1
- 1 : 1
Correct Option: D
(45° – θ) & (45° + θ) are complementary angles as 45° – θ + 45° + θ = 90° . We know that if angle of projection of two projectiles make complementary angles, their ranges are equal. In this case also, the range will be same. So the ratio is 1 : 1.
